[Tobi]

Hi all,

I am calculating a heated pipe (air = 800K) and do not want to simulate the air around that pipe but want to set a heat-transfer BC for that.

There for I thought its possible to work with the BC

wallHeatTransfer

but thats not working due to the turbulenceModel (not avaiable for the solid region).

So the question to you all: is there a other BC for that or some examples with groovy?

Thanks in advance.
Tobi

[billie]

Just that I got you right. The air with 800K is flowing around the pipe and heats it up. The heat conducts through the wall and in turn heats up the fluid within the pipe.

Instead of solving the air around the pipe you can either apply a heat flux or a heat transfer coefficient and the ambient temperature at the wall using the externalWallHeatFluxTemperature boundary condition.

[Tobi]

Originally Posted by billie

Just that I got you right. The air with 800K is flowing around the pipe and heats it up. The heat conducts through the wall and in turn heats up the fluid within the pipe.

Instead of solving the air around the pipe you can either apply a heat flux or a heat transfer coefficient and the ambient temperature at the wall using the externalWallHeatFluxTemperature boundary condition.

Hi,

in the attachement there you find a picture. I think that tells everyone more then words.

- in the pipe is air with T=800K and flows inside through the pipe.
- heat-transfer between fluid and solid due to chtMutli calculations

- at least I want to make the case more realistic. for that I want to create/calculate the heat transfer from the solid to the ambience air.


So my options are:

- building the air-domain and create a new mappedWall for pipe->new_air_domain
- or doing it with a BC like groovy?


Hope everything is clear now

[billie]

Okay so the air inside the pipe heats up the pipe walls and you want to add conduction on the outer wall of the pipe. I think the boundary condition I mentioned above should do the trick. Just use a negative heat flux or heat flux coefficient.

If you want somewhat correct solid temperatures you have to do this anyway else you will end up with 800K for the solid wall.

[Tobi]

Hi billie,

thanks for your replay.

The problem for the "heat flux" is that its not possible to calculate that.

The air = 800K changes in 1sec to 293K (thermal shock) and then the heat flux is completly different ... thats my problem.

[billie]

Originally Posted by Tobi

The problem for the "heat flux" is that its not possible to calculate that.

The air = 800K changes in 1sec to 293K (thermal shock) and then the heat flux is completly different ... thats my problem.

Sorry I meant convection on the outer pipe wall instead of conduction.

If you don't know the heat flux you can use the heat flux coefficient in combination with the ambient temperature.The convective heat transfer coefficient should be around 3-5W/m^2/K.

You can also estimate the heat flux coefficient using the formulas for natural convection of external flow around a cylinder from [1].

[1] http://en.wikipedia.org/wiki/Heat_tr...ral_convection

[phsieh2005]

Hi, Tobi,

To clarify what Daniel suggested. Use the following for the external wall of the pipe:

myPatch
{
type externalWallHeatFluxTemperature;
kappa solidThermo; // solidThermo or lookup
// q uniform 1000; // heat flux / [W/m2]
Ta uniform 300.0; // ambient temperature /[K]
h uniform 10.0; // heat transfer coeff /[W/Km2]
value uniform 300.0; // initial temperature / [K]
kappaName none;
}
-----------------

Pei-Ying

[Tobi]

Hi,.

thanks for your replay
But I figured it out by my self (-> code)

But thanks a lot

Tobi

[msarkar]

Hi Tobi,

You mentioned that you solved this yourself. Could please let me know what exactly you did? In your case did you model that pipe as a thick solid or solid thin wall? Did you use externalWallHeatFluxTemperature BC to a solid region?

Thanks in advance.
m sarkar

[Thamali]

Originally Posted by billie

Sorry I meant convection on the outer pipe wall instead of conduction.

If you don't know the heat flux you can use the heat flux coefficient in combination with the ambient temperature.The convective heat transfer coefficient should be around 3-5W/m^2/K.

You can also estimate the heat flux coefficient using the formulas for natural convection of external flow around a cylinder from [1].

[1] http://en.wikipedia.org/wiki/Heat_tr...ral_convection

Is this BC is possible to apply for enthalpy as well?

[aevub]

Originally Posted by msarkar

Hi Tobi,

You mentioned that you solved this yourself. Could please let me know what exactly you did? In your case did you model that pipe as a thick solid or solid thin wall? Did you use externalWallHeatFluxTemperature BC to a solid region?

Thanks in advance.
m sarkar

also interested

[Tobi]

Hmmm....

have a look at the availabe BC

[Lisandro Maders]

Originally Posted by Tobi

Hi,.

thanks for your replay
But I figured it out by my self (-> code)

But thanks a lot

Tobi

Hello Tobias,

I am performing a CHT simulation and I am not understanding how to set up a "h" (heat transfer coefficient) and "Ta" (ambient temperature) for my external surface of solid region (which has no contact with fluid region).

The externalWallHeatFluxTemperature BC mentioned by the other guys has as input parameters the wall layer thickness as well as the thermal conductivity, parameters that do not make sense because I have the solid region modelled.

I would like to do this without implementing anything if it is possible. If you managed to understand which BC does that, I would be gladded to know
In the case it is needed a code to do so, could you share yours?

Thank you,

Lisandro

EDITING: Actually, my confusion was that in the header of source code of this BC, it was saying that thicknessLayers and kappa were "Required". But actually looking at the code they are an option, so I believe it is doing now what I wanted: applying "h" and "Ta" in the surface..

Thanks anyway for the above discussion.