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#1 |
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Member
Pablo
Join Date: Mar 2009
Posts: 95
Rep Power: 6 ![]() |
Hello,
Why in alphaEqn.H is it not added alpha1 = max(min(alpha1, scalar(1)), scalar(0)); i mean this artificial bounded? Thanks |
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#2 |
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Member
Pablo Higuera
Join Date: Jan 2011
Posts: 99
Rep Power: 4 ![]() |
Hi
MULES solver ensures boundedness, that is why the last 2 inputs are 0 and 1, the bounds of alpha1. This is achieved by the use of limiters. The final result may show values greater than 1 or lower than 0, but with differences of the order of 10^-5, which is negligible. Regards |
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#3 |
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Senior Member
Santiago Marquez Damian
Join Date: Aug 2009
Location: Santa Fe, Santa Fe, Argentina
Posts: 371
Rep Power: 11 ![]() |
Using an artificial bounding of this kinds leads to a non-phase-preserving algorithm due it 'cuts' with having in account the conservative properties of the alpha equation. In other words you will lose or gain mass.
Regards.
__________________
Santiago MÁRQUEZ DAMIÁN, Ph.D. Post-doctoral Fellow Research Center for Computational Mechanics (CIMEC) - CONICET/FICH-UNL T.E.: 54-342-4511594 Ext. 1005 Güemes 3450 - (3000) Santa Fe Santa Fe - Argentina http://www.cimec.org.ar |
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#4 |
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Member
Pablo
Join Date: Mar 2009
Posts: 95
Rep Power: 6 ![]() |
But looking for steady state loss or gain mass is not going to be relevant or yes?
Thanks |
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#5 |
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Senior Member
Santiago Marquez Damian
Join Date: Aug 2009
Location: Santa Fe, Santa Fe, Argentina
Posts: 371
Rep Power: 11 ![]() |
Hhmm, I don't know, but since the solver is unsteady probably it will blow up before reach the steady state due mass preservation problems.
Regards.
__________________
Santiago MÁRQUEZ DAMIÁN, Ph.D. Post-doctoral Fellow Research Center for Computational Mechanics (CIMEC) - CONICET/FICH-UNL T.E.: 54-342-4511594 Ext. 1005 Güemes 3450 - (3000) Santa Fe Santa Fe - Argentina http://www.cimec.org.ar |
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