# Getting node of a position

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 March 2, 2013, 16:39 Getting node of a position #1 Senior Member   Mahdi Hosseinali Join Date: Apr 2009 Posts: 124 Rep Power: 8 How do you find the grid point that is near a location? The purpose is to calculate space correlation of a turbulence field which means: Code: `R(r)=/`

 March 3, 2013, 00:28 The most easiest way #2 Senior Member   Fumiya Nozaki Join Date: Jun 2010 Location: Yokohama, Japan Posts: 169 Rep Power: 7 I think the most easiest way to do your job is the following: Code: ``` vector pos(0.0,0.0,0.0); //Change the position as you like scalar limitLeng = 0.1; //Change the value as you like const cellList& Cells = mesh.cells(); const pointField& Points = mesh.points(); forAll(Cells, cellI) { if(mag(mesh.C()[cellI] - pos) < limitLeng) { forAll(mesh.cellPoints()[cellI], pointi) { //You can access labels of cell vertices label pointI = mesh.cellPoints()[cellI][pointi]; scalar r = mag(pos - Points[pointI]); //your stuff } } }``` Please post the codes, if there are more efficient ways. Hope that helps, Fumiya

 March 3, 2013, 08:37 #3 Senior Member   Laurence R. McGlashan Join Date: Mar 2009 Posts: 370 Rep Power: 14 The above code is unreliable, as the answer will be dependent on limitLeng. You are also not considering the situation where the nearest point to the location you are looking up may not be a part of the cell that it is inside of, although that will depend on how your mesh was constructed. primitiveMesh has a findCell function. Use that instead. If you want something more efficient then meshSearch uses an octree method for faster lookup. It doesn't work in parallel though so the location you lookup must be within the local mesh. anishtain4 and fumiya like this. __________________ Laurence R. McGlashan :: Website

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