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Jasak's Ueqn.

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Old   September 15, 2013, 22:44
Default Jasak's Ueqn.
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Dongyue Li
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Hi guys,

\begin{array}{l}
{a_p}{u_p} = \sum {{a_n}{u_n} - \nabla p,} \\
{a_p}{u_p} = \sum {{a_n}{u_n} - \int {\nabla p} dv} 
\end{array}

The first one in the famous Ueqn in Jasak's thesis. but isn't it should be the below one?

Thanks in advance.

Last edited by sharonyue; September 15, 2013 at 23:46.
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Old   September 16, 2013, 01:41
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Bernhard
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It would help if you give a more specific reference (i.e. equation number)
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Old   September 16, 2013, 04:15
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Quote:
Originally Posted by sharonyue View Post
Hi guys,

\begin{array}{l}
{a_p}{u_p} = \sum {{a_n}{u_n} - \nabla p,} \\
{a_p}{u_p} = \sum {{a_n}{u_n} - \int {\nabla p} dv} 
\end{array}

The first one in the famous Ueqn in Jasak's thesis. but isn't it should be the below one?

Thanks in advance.
Quote:
Originally Posted by Bernhard View Post
It would help if you give a more specific reference (i.e. equation number)
Its in his Ph.D. thesis page 145, 3.136.
I think its not correct, it should be:
{a_p}{u_p} = \sum {{a_n}{u_n} - \nabla p_f}
While it does not matter..do you think so?
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Old   September 23, 2013, 10:20
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Dongyue Li
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my bad. \int {\nabla p} dv .................. \nabla p_f
Jasak is rite, its a kind of semi-discretised form of equation. the pressure gradient is not discretised at this stage.
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