[haghgoo_reza]

Hello All,

it seems that phi in the icoFoam has the dimension of [meter cubed to time]. Hence the div(phi, u) has the dimension of [meter cubed to time squared]. On the other hand, it seems that ddt(U) has the dimension of [meter to time squared].
Apparently, they are dimensionally inconsistent.
can any body clarify it to me, please?

Moreover, what is the dimension of interpolate(HbyA) $ mesh.Sf()?

Thanks

[alundilong]

Originally Posted by haghgoo_reza

Hello All,

it seems that phi in the icoFoam has the dimension of [meter cubed to time]. Hence the div(phi, u) has the dimension of [meter cubed to time squared]. On the other hand, it seems that ddt(U) has the dimension of [meter to time squared].
Apparently, they are dimensionally inconsistent.
can any body clarify it to me, please?

Moreover, what is the dimension of interpolate(HbyA) $ mesh.Sf()?

Thanks

You will find mesh.Sf() only return geometrical data, if you take a look at $(FOAM_SRC)/finiteVolume/lnInclude/fvPatch.H. Hence, phi has unit of m/s.
Hope it helps!

[haghgoo_reza]

[QUOTE=alundilong;431245]You will find mesh.Sf() only return geometrical data, if you take a look at $(FOAM_SRC)/finiteVolume/lnInclude/fvPatch.H. Hence, phi has unit of m/s.


Thanks for your reply

I went through $(FOAM_SRC)/finiteVolume/lnInclude/fvPatch.H.but there was not anything as to phi.
Moreover, when you run the icoFoam for a 2-D cavity it creates a phi file inside time step folder saying that phi has the dimension of [m3/s].
could you please explain that to me?

Cheers

[fumiya]

Hi reza,

As you wrote, the flux phi has the dimension [m^3/s] (for the incompressible solvers).
The term div(phi, U) represents the convection term and it is discretized as written in the Eq. (2.16)
in the Programmers Guide(http://foam.sourceforge.net/docs/Gui...mmersGuide.pdf).
The F in this equation is phi and the dimension of this term after discretized using gauss integration
is [m^4/s^2](=m^3/s * m/s).

As to your last question, interpolate(HbyA) $ mesh.Sf() has the same dimension as the flux phi.

Hope this helps,
Fumiya

[alundilong]

Originally Posted by alundilong

You will find mesh.Sf() only return geometrical data, if you take a look at $(FOAM_SRC)/finiteVolume/lnInclude/fvPatch.H. Hence, phi has unit of m/s.
Hope it helps!

Please ignore my answer.
Sf() is a surfacevectorfield which does have dimension.