LaunderGibson - turbulent viscosity in epsilon equation
I'm inserting the LaunderGibson tubulence model to a two phase solver. Now I remarked that in LaunderGibson, in the transport equation for epsilon, a term DepsilonEff is used which contains the turbulent viscosity. Can someone explain why we have this viscosity? In my opinion, the great advantage of reynold stress models is the fact that we do not need the eddy viscosity assumption. So I'm a bit confused why there still is this turbulent viscosity...
Thanks for help in advance
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