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How to find whether the channel flow is fully developed?

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Old   March 4, 2013, 17:19
Default How to find whether the channel flow is fully developed?
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Jack
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Hi all,

I am doing simulation of channel flow using OpenFOAM. I have a question, how can we tell if the turbulence is fully developed? (by probe? or by simulation time? or else?)

Many thanks!
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Old   March 4, 2013, 19:11
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AFAIK, its done through statistical averaging of the flow field for a certain number of time steps or flow through times.If I'm not wrong, Fully developed turbulence is considered to be statistically stationary - So that might give you an idea. There are various factors in getting a developed turbulent field, and one of the most important ones is the simulation run time - theoretically, the longer you run, the more you average, the better the chances of getting statistically developed turbulence.

I'm no expert in the subject, but it might be very useful to go through these threads:

http://www.cfd-online.com/Forums/ope...nel-flows.html

Also, search for the "perturbU" code in the forums, and read the related threads. They have all that you would probably want to know.

Cheers,

A.T.M
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Old   March 4, 2013, 22:34
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Thanks very much, that helps me a lot!

Quote:
Originally Posted by atmcfd View Post
AFAIK, its done through statistical averaging of the flow field for a certain number of time steps or flow through times.If I'm not wrong, Fully developed turbulence is considered to be statistically stationary - So that might give you an idea. There are various factors in getting a developed turbulent field, and one of the most important ones is the simulation run time - theoretically, the longer you run, the more you average, the better the chances of getting statistically developed turbulence.

I'm no expert in the subject, but it might be very useful to go through these threads:

http://www.cfd-online.com/Forums/ope...nel-flows.html

Also, search for the "perturbU" code in the forums, and read the related threads. They have all that you would probably want to know.

Cheers,

A.T.M
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