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second derivatives in the navier stokes equation

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Old   March 27, 2014, 10:32
Default second derivatives in the navier stokes equation
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Gregory
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Dear all,

I just have a quick question:

are the second derivatives in the navier stokes equation symmetric? In other words:

d/dx d/dy ux(x,y) = d/dy d/dx ux(x,y) ? where ux is the x-component of the fluid velocity.

Thanks for your response!
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