paper request
Hi Dear FOAMers
May any one tell me how can I get the paper "Drop impact onto a liquid layer of finite thickness: Dynamics of the cavity evolution"? Best regards |
Hi ata give me your email I.D . I can send it to you.
regards K.Suresh kumar |
Hi Kumar
I sent you via a private message in the forum. Thank you very much |
Hi ata,
Could you send me paper "Drop impact onto a liquid layer of finite thickness: Dynamics of the cavity evolution"? My email: alexeyginevsky@gmail.com Thank you in advance. |
Drop impact onto a liquid layer of finite thickness Dynamics of the cavity evolution
Hi
I sent it. Good luck |
Hi ata,
please could you send me your paper "Drop impact onto a liquid layer of finite thickness: Dynamics of the cavity evolution", too? My email: klaus@rt.tu-cottbus.de Thanks in advance. linoth |
Hi
I sent it. Good luck |
Dear foamer
I have review the code of interFoam and interPhaseChangeFoam. However, I can't understand the function usage of MULES. It write in interPhaseChangeFoam: MULES::explicitSolve(oneField(), alpha1, phi, phiAlpha, Sp, Su, 1, 0). What mean does 'Su' in the code. Anybody can me a reference about MULES method? |
Sp and Su are implicit and explicit source terms (e.g. for cavitation simulations).
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fvScalarMatrix pEqn |
Because there is no fvm::Su() function. Explicit source terms are used without any additional notation.
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00032 template<class Type> Code:
00098 template<class Type> |
Mea culpa! I do still believe that writing "fvm::Su((vDotvP-vDotcP)*pSat, p)" is equivalent to "(vDotvP-vDotcP)*pSat*p". Anyway, I think the gist of your question is why the source term is treated implicitly? My guess is that (vDotvP-vDotcP) is usually larger zero, so when including the expression in the matrix instead of moving it to the right hand side of the equation system you will increase diagonal dominance.
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Dear all
I need a reference which describes by more details the new local-time stepping (LTS) approach applied in VOF in openfoam. Thanks |
Summary + some questions
I found this thread when I was looking for reference documentation for InterFoam, and decided to make like a short summary of it and at the same time ask some interesting questions that I think is still left unanswered.
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--Pharg |
Hi All,
I found all of you guys are working around VOF method, I am a newbie here, but I am facing a problem regarding the changeable viscosity in VOF. For example: if the liquid is kind of non-newtonian fluid. More details I wrote it here, http://www.cfd-online.com/Forums/ope...-wierd-nu.html Can you guys help me check this out? Is this a problem only regarding with the viscosity model or with VOF? Thanks in advance. |
@isabel
" In the interFoam solver, what these lines in the file gamma.Eqn.H mean? surfaceScalarField phiGamma = fvc::flux ( phi, gamma, gammaScheme ) + fvc::flux ( -fvc::flux(-phir, scalar(1) - gamma, gammarScheme), gamma, gammarScheme ); " this refers to the compression term used in MULES. note (gamma) and (1-gamma). These filter the velocity field and gives us a way to evaluate Ur = U1 - U2 which is used in the interface compression term. Also look up fvcFlux.* in your install directory. this will shed some light on what phiGamma becomes. see: http://infoscience.epfl.ch/record/130534 and http://powerlab.fsb.hr/ped/kturbo/Op...chePhD2002.pdf to see the interface compression term. |
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Since this post is very old and some of you might have dig into the code. Hence, I am posting my doubt in this thread. If we look at the MULES solver as pointed by SM Damian, new flux is assembled for the momentum equation. Doubt: In case of interface, the "rhoPhi" term can be easily related to the equation. Now, How to relate the "rhoPhi" term for the phase 1 or phase 2 cells (where no interface is present)? Please correct me, if I misinterpret anything. - Thanks in Advance :) |
Dear All,
Thanks again for your time. I have understood the term "rhoPhi". Hence I am sharing this info, may be it will be beneficial to others. For phase 1: rhoPhi = phi*rho1; For phase 2: rhoPhi = phi*rho2; For interface: rhoPhi = phiAlpha*(rho1 - rho2) + phi*rho2; - :) |
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