I am using simpleFoam with kEp
I am using simpleFoam with kEpsilon model. After few iterations it looks like it stops solving equations of k and epsilon as I don't see error on my terminal. Does this mean that these equations diverged? How to make it visible all the time. I have experimented with "tolerences" as well as "relaxation factors" no improvement.
Regards GS 
Maybe the initial residual is
Maybe the initial residual is less than tolerences, so these equations don't need to be solved. Steady state?

Yes, steady state, I was guess
Yes, steady state, I was guessing the same, but I still want to solve. How do I do that.
Regards 
Do you see the initial residua
Do you see the initial residual fall? Does it drop below your convergence tolerance? Have you tried making the convergence tolerance very tight?

>Do you see the initial residu
>Do you see the initial residual fall?
Yes, initially there is reduction in residual. >Does it drop below your convergence tolerance? Yes >Have you tried making the convergence tolerance very tight? Yes Currently I am compiling the code by making following change in "tests.C" //converged_ = true; converged_ = false; Will this help? Regards GS 
I would be able to help you mo
I would be able to help you more if I had the answers to my questions or better still a section of the log file from just before kepsilon stop solving to just after.

Sorry, I missed the answers bu
Sorry, I missed the answers buried there. Anyway, I would still like to see the section of log file. Have you looked the the field valeus for kepsilon? Are they VERY large?

BICCG: Solving for Ux, Initia
BICCG: Solving for Ux, Initial residual = 0.0114222, Final residual = 0.000931753, No Iterations 1
BICCG: Solving for Uy, Initial residual = 0.0227955, Final residual = 0.00190204, No Iterations 1 BICCG: Solving for Uz, Initial residual = 0.00691902, Final residual = 0.000593082, No Iterations 1 ICCG: Solving for p, Initial residual = 0.0216008, Final residual = 0.000214944, No Iterations 116 time step continuity errors : sum local = 0.00871451, global = 0.000437168, cumulative = 0.0171293 BICCG: Solving for epsilon, Initial residual = 0.021943, Final residual = 2.2619e08, No Iterations 1 BICCG: Solving for k, Initial residual = 1.78372e05, Final residual = 1.1457e06, No Iterations 1 ExecutionTime = 201 s Time = 257 BICCG: Solving for Ux, Initial residual = 0.0114393, Final residual = 0.000938528, No Iterations 1 BICCG: Solving for Uy, Initial residual = 0.0228175, Final residual = 0.0019204, No Iterations 1 BICCG: Solving for Uz, Initial residual = 0.00691351, Final residual = 0.00059707, No Iterations 1 ICCG: Solving for p, Initial residual = 0.0229688, Final residual = 0.000222948, No Iterations 115 time step continuity errors : sum local = 0.00902571, global = 0.000449829, cumulative = 0.0175791 BICCG: Solving for epsilon, Initial residual = 0.0225105, Final residual = 2.18334e08, No Iterations 1 bounding epsilon, min: 3.5104e12 max: 822122 average: 4651.92 ExecutionTime = 205.23 s Time = 258 BICCG: Solving for Ux, Initial residual = 0.0114469, Final residual = 0.00095594, No Iterations 1 BICCG: Solving for Uy, Initial residual = 0.0226974, Final residual = 0.00194632, No Iterations 1 BICCG: Solving for Uz, Initial residual = 0.00688176, Final residual = 0.000596608, No Iterations 1 ICCG: Solving for p, Initial residual = 0.0220571, Final residual = 0.00021926, No Iterations 118 time step continuity errors : sum local = 0.00883914, global = 0.000396233, cumulative = 0.0179754 Will this help to clarify myself? You can see after Time(iteration) # 257, k and epsilon disappears forever. Regards GS 
What convergence tolerance hav
What convergence tolerance have you set for k and epsilon?

For both 1e5(Tolerance), 0.1(
For both 1e5(Tolerance), 0.1(RelativeTolerance)

For cases will wallfunctions
For cases will wallfunctions I use 1e8.

Now I am running with 1e15 an
Now I am running with 1e15 and 0.1 for both. It appears again. This way what is the lower tolerence limit?
Thanks and regards GS 
Check the k and epsilon fields
Check the k and epsilon fields, it sounds like they are becoming VERY large which affecting the residual normalisation.

Max epsilon is 676404.2 m^2/s^
Max epsilon is 676404.2 m^2/s^3 and k is 72 m^/s^2, which is not too large value.
It has disappeared again even after giving tolerance 1e15 for both k and epsilon. Regards GS 
It appears k and epsilon have
It appears k and epsilon have converged for your case.

But I do not want it to stop s
But I do not want it to stop solving k and epsilon, as flow field is still developing. How do I do that?
Regards GS 
For some reason, probably due
For some reason, probably due to something in your setup/BCs, the kepsilon system has converged and nothing you do to the tolerances will make it converge further. You need to find out what is wrong with your setup.
We would be happy to check and correct your case as part of your support contract with OpenCFD. 
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