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Which Solver should I choose?

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Old   June 4, 2011, 13:51
Default Which Solver should I choose?
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Mike
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Hello,
I would like to simulate incompressible laminar flow over a semi-infinite flat plate at zero incidence, with constant density throughout the flowfield.

The thing is that I want to compare the results that I will get with OF, with a homemade algorithm that I have built in FORTRAN, that simply solves the Continuity and X-Momentum equations, like listed in the attachment.

I am thinking of choosing icoFoam or simpleFoam with turbulence turned off, but I can't understand how they are different (Transient vs Steady State solver) and what will the impact on my obtained solution be.

If anybody has a remark, I would be grateful

Mike
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Old   June 4, 2011, 14:04
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If you are interested in steady state solution, u can opt for simpleFoam.
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Old   June 4, 2011, 14:13
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So, if I choose simpleFoam, what would be a reasonable value for timeStep in ControlDict? Should I set timeStep= 1 sec and run until convergence?
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Old   June 4, 2011, 16:38
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Alberto Passalacqua
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Yes, and if you want 1D case, create a mesh with only one cell in the Y and Z direction.

Best,
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Old   June 6, 2011, 17:09
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Well, I want to increase Reynolds (~10^7) so that I have turbulent flow. I used k-epsilon model. I just introduced 2 files (k and epsilon) under 0 folder and the necessary fvschemes and fvsolution modifications. Is this correct? Or do I need other changes and files under 0 folder, like nutilda ?

And after that, how can I plot the u-velocity in gnuplot or paraview (if possible), towards timesteps ?

Thanks!

PS: i added 2 images. The first is the laminar fully developed boundary layer and the second is the turbulent fully developed boundary layer.
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File Type: jpg turbulent.jpg (20.3 KB, 20 views)

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Old   December 13, 2011, 14:38
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mikemech, Alberto....

why would one need to give a time step to this type of problem, when you are doing steady-state simulation??? if you have steady-state the time dependence would disappear wouldn't it??? Thanks


-Ricardo

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Originally Posted by alberto View Post
Yes, and if you want 1D case, create a mesh with only one cell in the Y and Z direction.

Best,
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Old   December 14, 2011, 00:47
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Originally Posted by rvmedina20 View Post
mikemech, Alberto....

why would one need to give a time step to this type of problem, when you are doing steady-state simulation??? if you have steady-state the time dependence would disappear wouldn't it??? Thanks


-Ricardo
In steady-state solvers, the time-step is just a counter for the number of iterations. Simply use 1.
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