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the droplet diameter according to the rate eq. (implicitly)Hello everyone,
I have a question about the droplet diameter rate equation in the breakup model: In many paper this rate equation is like following: dr/dt=-(r-rc)/t_brekup But in the breakup models e.g. PilchErdman and ReitzDiawakar the rate equation is implemented as following: d = (d + frac*Ds)/(1.0 + frac) I do not know why it is so implemented. In my opinion it should be like following: d = d - d*frac + frac*Ds Does anyone also meet this problem. Thanks in advance Chenkai |

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