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oldTime() outputting current time value:

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Old   August 9, 2012, 10:33
Default oldTime() outputting current time value:
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Dear all,

I have a solver with an outer time loop, and inner loop with sub-iterations. In order to check the convergence of the outer and inner iterations, I wanted to access my field values at the
- previous time step: p.oldTime()
- previous inner iteration: p.prevIter()

While prev.Iter() seems to work fine, I am encountering issues with oldTime() and was wondering if I was doing something wrong.

I am storing values with storePrevIter(), should I use something else for oldTime()?

Another option is that there may be a memory issue with oldTime:
when one adds print statements before modifying a field value, then oldTime() is stored properly whereas it is not without the print statement (which seems fishy)


Playing around with the problem, I wrote a very simple code (attached) with the following algorithm, and a set-up ready to run (though the example code really can run on any case)
Code:
DP=1
for( time )
    p.storePrevIter()
    //comment 1: print DP.oldTime()
    for( innerIteration<2 )
    {
        DP.storePrevIter()
        DP+=DP
    }
    //comment 2: print p.oldTime()
    p = DP
without any print statement, the values at the end of the first time steps are:
p[0] oldTime, prevIter, current = 4 1 4
DP[0] oldTime, prevIter, current = 4 2 4

with the print statements in comment 1 and 2, the values are properly stored and read as:
p[0] oldTime, prevIter, current = 1 1 4
DP[0] oldTime, prevIter, current = 1 2 4


Any help on that problem would be great,
Diane
Attached Files
File Type: zip OldTimeProblem.zip (32.6 KB, 2 views)
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