# forceCoeffs and rhoInf dependency

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 July 5, 2013, 16:29 forceCoeffs and rhoInf dependency #1 Member   Florian Join Date: Nov 2009 Posts: 59 Rep Power: 9 Hello, I have an incompressible simpleFoam solution of a flow field. I use forceCoeffs to calculate Cd etc. on some patches. Code: ```coeffsCar { type forceCoeffs; functionObjectLibs ( "libforces.so" ); outputControl timeStep; outputInterval 10; patches \$carPatches; pName p; UName U; rhoName rhoInf; log true; rhoInf 3; liftDir (0 0 1); dragDir (1 0 0); pitchAxis (0 1 0); CofR (0.56725 0 -0.1274); magUInf 45; lRef 1.5; Aref 0.4;``` I tried it on exactly the same case, one time set rhoInf to 3, another time to the actual value of 1.4. Both forceCoeffs got me exactly the same results, regardless of the value of rhoInf. Is there some bug in OF 2.1.1 or a bug in my understanding of physics? Force on a patch is F=p*A, drag coefficient is Cd = F / (0.5 rhoInf U^2). Why is there no influence of rho? Thanks!

 July 24, 2013, 13:51 #2 Senior Member   Joachim Join Date: Mar 2012 Location: Atlanta Posts: 140 Rep Power: 7 Hi Florian, if the solver is incompressible, the pressure computed by OpenFOAM is p/rho and not p. Hence, you don't need to know the density to get your coefficient (just divide your pressure force by 0.5*Ue^2 A). You can write anything you want for the density in forceCoeffs, it is not read when computing the coefficients. Regards, Joachim

 July 25, 2013, 10:04 #3 Member   Florian Join Date: Nov 2009 Posts: 59 Rep Power: 9 Yeah, that became clear after posting this. But I'm still riddled why OF requires setting a value of rhoInf. In the source code, as far as I can tell, it's determined by units if p' = p/rho (incompressible) or p' = p. Regards...

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