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Old   May 14, 2009, 04:25
Question Chanel flow+bc
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boris brangeon
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Hi,

I don't understand how to create the BC, with OpenFOAM, at the inlet level of the open channel?

outlet
| |
| |
| |
| |
left | |right
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inlet


INLET :\frac{\partial w}{\partial z}=0, u=0 , \Theta=0 , Pm=-0.5U^{2}

RIGHT(black) : adiabatic; \Theta=0

LEFT : (red=hot)\frac{\partial \Theta}{\partial x}=-1, u=w=0 ,\frac{\partial Pm}{\partial x}=0


OUTLET : -\frac{\partial u}{\partial x}=\frac{\partial w}{\partial z}=0, \frac{\partial \Theta}{\partial z}=0 , Pm=0


Thank you .

Last edited by boby; May 15, 2009 at 10:37.
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