[momo_sjx]

Hi, everyone,

I encounter a problem when I want to define an interior interface.
In a flow field, there is an airfoil.
I draw a circle around the airfoil, because I want to know how do the pressure and velocity response when the flow conditions change.
I can post-process it, which is not convenient.
So can I define an interior interface in the SU2, thus I can read the data from the .csv easily.
How to define it in SU2?

Thank you very much.

[fpalacios]

Originally Posted by momo_sjx

Hi, everyone,

I encounter a problem when I want to define an interior interface.
In a flow field, there is an airfoil.
I draw a circle around the airfoil, because I want to know how do the pressure and velocity response when the flow conditions change.
I can post-process it, which is not convenient.
So can I define an interior interface in the SU2, thus I can read the data from the .csv easily.
How to define it in SU2?

Thank you very much.

To define an interior surface you can create with the grid generator a double surface (two different surfaces with coincident points) and use MARKER_INTERFACE=(inner_surface, outer_surface).

Just defining a surface (without a boundary condition) could work, but we should double check the final result.

Cheers,
Francisco

[momo_sjx]

Thanks.
This interface is virtual and defined for convenient analysis.
I defined this surface in grid.su2, but if I did not give a boundary definition, it would not work.
So current method I use is
1) save the elements/nodes on these interfaces
2) remove them from grid.su2
3) run the case
4) read the result files and grab the variables at the interface.
It is not difficult for programming, but very slow, as each result file is about 1G and I have 400 files.
I am looking forward to more output options in the future SU2.

Looking

Originally Posted by fpalacios

To define an interior surface you can create with the grid generator a double surface (two different surfaces with coincident points) and use MARKER_INTERFACE=(inner_surface, outer_surface).

Just defining a surface (without a boundary condition) could work, but we should double check the final result.

Cheers,
Francisco