[Renu123]

If I have a plane, is there a quick way to get the normal vector? (just a simple plane, no surface, no edges or points).
def main():
# creating a plane
x1,y1,z1=500,90,200
x2,y2,z2=50,100,200
x3,y3,z3=600,30,45
plane_1=base.CreateWplane3Points(x1,y1,z1,x2,y2,z2 ,x3,y3,z3)

[maddoxx]

Hi,
I am new to this forum. And glad to help you on this one.
Function takes 3 point ordinates [x1,y1,z1],[x2,y2,z2],[x3,y3,z3].
And returns unit vector for the plane formed by the 3 points

import ansa

def normalVector2Plane(pnt1,pnt2,pnt3):# 3 points 
	def vector(point1,point2):
		delx=point2[0]-point1[0]
		dely=point2[1]-point1[1]
		delz=point2[2]-point1[2]
		magnitude=(delx*delx+dely*dely+delz*delz)**0.5 # Distance from Distance Formula
		if(magnitude!=0):
			x=delx/magnitude
			y=dely/magnitude
			z=delz/magnitude
			return [x, y, z] # Unit Vecor
		else:
			return 0
	a = vector(pnt1, pnt2)
	b = vector(pnt1, pnt3)
	return ansa.calc.CrossProduct(a, b) # Cross Product of 2 Vectors

[Renu123]

Originally Posted by maddoxx

Hi,
I am new to this forum. And glad to help you on this one.
Function takes 3 point ordinates [x1,y1,z1],[x2,y2,z2],[x3,y3,z3].
And returns unit vector for the plane formed by the 3 points

import ansa

def normalVector2Plane(pnt1,pnt2,pnt3):# 3 points 
	def vector(point1,point2):
		delx=point2[0]-point1[0]
		dely=point2[1]-point1[1]
		delz=point2[2]-point1[2]
		magnitude=(delx*delx+dely*dely+delz*delz)**0.5 # Distance from Distance Formula
		if(magnitude!=0):
			x=delx/magnitude
			y=dely/magnitude
			z=delz/magnitude
			return [x, y, z] # Unit Vecor
		else:
			return 0
	a = vector(pnt1, pnt2)
	b = vector(pnt1, pnt3)
	return ansa.calc.CrossProduct(a, b) # Cross Product of 2 Vectors

Thank you I will try it.