Curved Tube Using a Two Phase Approach
 

Good Afternoon CFD Online

I'm trying to simulate the following geometry but I need some help about how to draw it correctly as the way of drawing 2D face and then Revolve or Sweep is using for the first time.

http://s28.postimg.org/5vgxyqqvx/image.jpg



Then, when I mess some of 3D geometries I could not get the following as I'm using Hex/Wedge and Cooper


http://s23.postimg.org/khxu2854b/image.jpg

Create one section (disk)
Create one edge which will describe your center line
Then you can sweep your face (disk) with your edge, and you get your 3d volume.
Now if you want a full hexa mesh (no pave), you have to split your domain. By decomposinf it, you will get a nice hexa mesh.
In your case, the decomposition is O-grid type.
Typically you draw a square inside your disk, and you split your disk with the square. Check here for instance: http://www.cfd-online.com/Forums/ans...id-gambit.html

First of all ,
For drawing 3D Pipe O-rigid. I followed a new way to get that pipe
and my pipe is below, take a look and then give your evaluation

And For my thread. I made a circle face and to connect the center line with that circle I did not get the method. with pictures if don't mind

This is not an O-grid. Doing this you won't be able to mesh the inner pipe with hexa (but with pave you will)


As I said, you need to have a square inside your disk

http://www.cfd-online.com/Forums/ansys-meshing/124634-how-plot-s-pipe.html

Okay MAX
if I considered my geometry as presented above as a concentric annuli is my procedure correct from drawing and meshing

To connect the arc with the Slice have faced a problem as below
I used Radius 20 mm for both the arc and the face

is the yellow edge the path for sweeping?
if yes, then it cannot be coplanar to your disk

Yes Max the yellow edge is the path of sweeping
I did point in the center of disc to be the center of that path got this

your edge has to belong to (xz) plane

Even with XZ failed

Now the face in XY and the path in XZ

align your edge with your disk so that 2 points are coincided
Then in sweep too select perpendicular type
Attachment 33197

Attachment 33198

Let copy your dimensions in last two pictures

1- Radius of Disc is ( ? ) and xz plane right?
2- Selecting circular arc with the third method
Radius is ( ? )
Start angle ( ? )
end angle ( ? )
the center you selected the vortex of the disc or how

and also you selected xz plane


Sorry for my too much quires

1- 15 in (xy) plane
2- just like yours , ie :
*radius 40
*start angle 0
*end angle 210
*(zx) plane
then you need to rotate your edge with 90° angle along (0 1 0)

Now so-so
I got the geometry but what happened I didn't understand why?
Maybe my directions or orientations .

I followed all yr instructions

* Disk with 15
* Arc with 40 and 0-210 angles of start and end. The center was the disk vortex .
Than I did rotation to the path line and finally sweep with perpendicular type but I got this

*create a plane with 500x500 (zx)
*split your tube with the plane, you will get 2 symetric domains.
Delete one and check if the geometry is ok
Attachment 33202

I did your last point but as I told you something goes wrong !!!!!

if you don't explain what the problem is, I cannot help you.
From your pictures everything seem to be ok

Dear Max ..

My problem is before doing sweep, the disk and Arc-Path r connecting wrongly Not like yours. For that just take a look at the last picture after splitting the geometry by that plane

It doesn't make any difference.
Interpret this edge as a vector.
Important, is the way to build your geometry: and you did it correctly