# Closing on wall functions - part 3: a standard wall function

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# Closing on wall functions - part 3: a standard wall function

Posted April 23, 2022 at 05:41 by sbaffini
Updated May 15, 2022 at 03:20 by sbaffini

We make the following assumption for the turbulent viscosity ratio: where is the von Karman constant and is, for the moment, an unspecified positive parameter. One can then show that the following results:  where , , and: The general problem with the standard formulation is that, while it is reasonable to pick up an value for the velocity case, even a second one for the TKE production (rigorous doesn't mean stupid, so if different values work better for and , why not?), it is not reasonable to manually pick a value in for each value of the ratio .

As it turns out, however, the above formulation requires modifying only for , but just works in all the other cases. This statement just accounts of the fact that for the turbulent viscosity ratio becomes less and less important, while it becomes more and more important in every detail when multiplied by the ratio .

The case is correctly accounted by the present formulation because it has not neglected the 1 at the denominator of the integrand function in and because the solution is not arbitrarily expressed in terms of the velocity one with all the logarithmic constants lumped in a single one (typically E). The fact that the formulation still doesn't work for is just a statement of the fact that, in this case, the turbulent viscosity ratio becomes important for the temperature distribution before it does for the velocity one, so in must be reduced. Let's call this new value (yet, this is only needed for ).

As the Jayatilleke P term exactly embeds this exact same concept, it is easy to show that it can be used by computing from the following non linear, implicit equation (a similar one must be solved also for the classical standard wall function): where is the original value used in the velocity profile and P is the mentioned Jayatilleke term (but any similar correlation can substitute it in the equation above, say the Spalding one). I have found that, initializing as , 3 iterations of the Halley's method are sufficient to compute close to machine precision for any practical value of .
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