which turbulence model should I choose?
Hi everyone,
I try to simulate different velocity flow(turbulent flow) in a planar tube. Attachment 19909 However, no matter which turbulence model I choose, the results all seem as laminar. Can anyone tell me whats the problem? Thx. Regards, itsqi7 |
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This is the structure.Attachment 19910
These are simulation results of k-e and SST[ATTACH]Attachment 19912[/ATTACH] However, after I defined the side walls as symmetry, both turbulent model can get turbulent flow. [ATTACH]Attachment 19914[/ATTACH] Is that because the planar tube is too thin? |
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If the two bounding planes are walls then the effective Re number of this thing is much reduced and turbulence will dissipate very quickly - like you are seeing.
What are you trying to model? A 2D diffuser? What have you used for boundary conditions on the top and bottom bounding planes? |
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Thanks for ur reply. I want to simulate a 3D diffuser and by default I set all the boundaries except inlet, outlet as non-slip wall. Regards, itsqi7 |
That is the problem then. You have reduced the Re number and increased turbulence dissipation by having lots of walls. If you want this to better represent a 3D diffuser either use symmetry planes for the top and bottom planes, or even better translational periodic boundaries.
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Interestingly, the turbulence kinetic energy only changed in a tiny region near the inlet of diffuser, which can be seen in the picture.Attachment 19932 Detail of contour.Attachment 19933 But I still don't understand what caused "the reduced Re number" and what is the meaning of using symmetry planes for top and bottom planes. Could you please briefly explain this? Thanks. |
Have a look at the hydraulic radius for your shape.
Also, you will get less turbulence dissipation with translational periodic boudnaries rather than symmetry planes. It is all a matter of how many degrees of freedom you are constraining - if the FEA analogy makes sense to you. The reverse flow is probably due to a separation and is probably real. Then you will ned to extend your domain further downstream. |
Is the cross section of your diffuser circular or rectangular? If it is circular, you may want to use an axisymmetric wedge rather than 2D geometry you are currently using.
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It makes perfect sense to use symmetry boundary condition at the side walls, as you showed in post #3. This way, the velocities will not be resisted by walls and Re would be higher, producing turbulent flow. Although, I didn't understand why Glenn suggested using symmetry at top and bottom bounds. If I am not missing something, this doesn't sound right. They should be no-slip walls. But the big side walls should be symmetry. If the cross section of your diffuser is rectangular, then it makes sense to use translational periodic condition at the two big parallel side walls. OJ |
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Well, I realize that you were referring to the top most image, and I was referring to the bottom images. Two are oriented differently :)
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I think I misunderstand your point about top side either.:) The pic in post#3 is the result of setting big side walls as symmetry boundaries, and the pics in post#7 are the results of setting small side walls as symmetry boundaries(Although I don't know why you suggested that then...). Your suggestion is to set big side walls as either symmetry or translational periodic boundaries, right? But doesn't this simulate an infinite thick diffuser? What I want to simulate is the flow in a rectangular cross section as in the pics rather than a thick one. Thanks a lot for ur and OJ's help. jiaqi |
Yes, both the symmetry plane and translational periodicity approaches are simulating infinitly ducts.
But if the geometry you show is what the true 3D shape of this thing is then you should expect it to have a lot of turbulence dissipation in it. Have you worked out the Re number of the flow? I would use the thin dimension of the thickness for the length scale, not the larger cross dimension. That will tell you how turbulent the flow is going to be. |
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I set the inlet flow rate as 1m/s, and the narrowest cross section is 2mm*10mm. So Re should be 3.3e3. I think this Re should have turbulent flow. Anyway, even I set the inlet flow rate as 100m/s, there is still no turbulent flow. I don't know whether it's the right answer. But when I use the result to calculate the pressure recovery coefficient, it seems that it does not confirm with the real situation. Regards, itsqi7 |
Re=3300 is a very low turbulence flow. You will not get much turbulence in it at the best of times. Also, many turbulence models (k-e especially) are designed for high Re flow and do not function well at low Re like this. You are going to carefully choose a turbulence model to be appropriate for this flow.
When you say "these is still no turbulent flow", how are you reaching that conclusion? Anywhere the k value is more than zero you have turbulent flow. |
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Also, for Re 3300, have you tried low Re models or transitional models? OJ |
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I used SST model to simulate this low Re flow. You are right. I misunderstood the 'turbulent flow'. I thought there should be back flow. Actually for even low Re there is k value more than zero near the side but no back flow shown in the contour. This phenomenon is what I want to get, just not obvious:) Thanks a lot for your help. Regards, itsqi7 |
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I think I got the result but thought it was wrong... Please see the above post. Thanks very much for your help. Regards, itsqi7 |
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It sounds like you are still misunderstanding turbulent flow. Turbulence is NOT recirculations, back flow and/or transient flow. Turbulence IS 3D transient flow which has a wide range of time and length scales, right down to the microscopic level (the turbulent energy cascade) - see any turbulence textbook for more discussion on this definition.
So separations, flow instability, recirculations and transient flow can still occur in laminar flows - but they will not have time and length scales down to the microscopic levels. |
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