# Resultant force magnitude and direction in CFX-post

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 April 8, 2009, 08:47 Resultant force magnitude and direction in CFX-post #1 New Member   Join Date: Apr 2009 Posts: 1 Rep Power: 0 Dear friends, I have a cylindrical surface pressure distribution. I would like to find out the resultant force magnitude and direction due to the pressure on that surface. How to do it in CFX-Post?. What is the difference between the following two approaches: 1. Function: AreaInt (Variable: Pressure) at the selected location in a certain direction 2. Function: Areaavg(Variable: Force) at the selected location I think, they both should give same answer, but they are not. Perhaps, I am not understanding it right. It would be great help, if someone explain the difference between them. Thank you.

 April 8, 2009, 20:31 #2 Super Moderator   Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 14,080 Rep Power: 109 Hi, The area integral of pressure does not include wall shear. The best way to get the total force on a surface is using the force_x()@Surface command. Glenn Horrocks

 March 19, 2013, 04:52 Regading the same problem as discuss above. #3 New Member   Abhishek Join Date: Nov 2011 Posts: 6 Rep Power: 8 Hello All, Greetings! @Mr. Glenn Horrocks ; How to find the location of the resultant force using the geometry and pressure distribution?

 March 19, 2013, 05:29 #4 Super Moderator   Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 14,080 Rep Power: 109 You can calculate it from the force_x() and torque commands. I will leave the derivation of the equations up to you - here's a hint.... torque = force x distance.

 March 19, 2013, 08:11 #5 New Member   Abhishek Join Date: Nov 2011 Posts: 6 Rep Power: 8 Hello Mr.Glenn Horrocks, Thanks for quick reply and suggestion. However, It's not solve our purpose. We have annular cavity with some thickness, we find out the pressure distribution over inner and outer surface. also calculate the forces in YZ plane and length in X-direction. Using this we have calculate resutant force and angle. But we could not have idea to find the location i.e x distance, in X-direction i.e axially. As your suggested that calculate torque and then using this it would be possible to calculate the distance. However, the CFX gives the torque in y and z direction too. but we don't have constraint to our geometry. If you have more views on the same, Let me know. Thanking you! Last edited by abhishekchitvar; April 8, 2013 at 01:05.

 March 19, 2013, 09:52 #6 Senior Member   Edmund Singer P.E. Join Date: Aug 2010 Location: Minneapolis, MN Posts: 512 Rep Power: 14 Resultant force location is not unique. It is a vector. Fix one of your points (perhaps on your body) and the other points will fall out.

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