[rogbrito]

Hello, folks!

I would like to know in how to increase the decimal point numbers of temperature in .out file or when I am exporting the data in CFX-Solver by a monitoring point (cartesian Coordinates = 4.3 [mm], 3.5 [mm], 4.7 [mm])? My problem is described below and the files (hexahedrical mesh files, initial and boundary conditions .CCL file, and temperature field results obtained with my own code from our project group) of this simulation is inside of this post. I´ve been used others trial softwares and I had the results that I want. (but I can´t use others trial softwares, because we intend to use ANSYS CFX even so)

Thanking you in anticipation,

Rogerio.


Thermodynamic State = Solid
Density = 14900 [kg m^-3]
Molar Mass = 1.0 [kg kmol^-1]
SPECIFIC HEAT CAPACITY:
Specific Heat Capacity = 508.1237 [J kg^-1 K^-1]
THERMAL CONDUCTIVITY:
Thermal Conductivity = 73 [W m^-1 K^-1]
ANALYSIS TYPE:
Option = Transient
TIME DURATION:
Option = Total Time
Total Time = 110.778 [s]
TIME STEPS:
Option = Timesteps
Timesteps = 0.222 [s]
BOUNDARY: Conveccaoo
Boundary Type = WALL
Location = ASM.1 CONVECCAOTOTAL
BOUNDARY CONDITIONS:
HEAT TRANSFER:
Heat Transfer Coefficient = 20 [W m^-2 K^-1]
Option = Heat Transfer Coefficient
Outside Temperature = 29.34 [C]
Boundary Type = WALL
Location = SOL_2D_REGION
BOUNDARY CONDITIONS:
HEAT TRANSFER:
Heat Flux in = 1.0 [W m^-2]
Option = Heat Flux
INITIAL CONDITIONS:
TEMPERATURE:
Option = Automatic with Value
Temperature = 273.15 [K]
MONITOR POINT: T4
Cartesian Coordinates = 4.3 [mm], 3.5 [mm], 4.7 [mm]
Option = Cartesian Coordinates
Output Variables List = Temperature
CONVERGENCE CRITERIA:
Residual Target = 0.00000001
Residual Type = RMS
TRANSIENT SCHEME:
Option = Second Order Backward Euler
TIMESTEP INITIALISATION:
Option = Automatic
SIMULATION CONTROL:
EXECUTION CONTROL:
EXECUTABLE SELECTION:
Double Precision = On

[rogbrito]

Anyone could help me , please? I´d like that ANSYS CFX 12 will export the temperature results with more decimal points, for example:


t[s] T[K]
0.0 273.15000001
0.1 273.15000006
0.2 273.15000007
... .....


The results of our own code, in C and for heat flux equal to 1.0 [W m^-2], are described below (time in [s] and temperature in [ºC]):

title = "T.dat"
variables = "time" "Temperature"
2.22000E-01 1.84826E-06
4.44000E-01 5.66649E-06
6.66000E-01 1.08146E-05
8.88000E-01 1.67155E-05
1.11000E+00 2.30114E-05
1.33200E+00 2.95083E-05
1.55400E+00 3.61058E-05
1.77600E+00 4.27536E-05
1.99800E+00 4.94264E-05
2.22000E+00 5.61116E-05
2.44200E+00 6.28030E-05
2.66400E+00 6.94975E-05
2.88600E+00 7.61935E-05
3.10800E+00 8.28902E-05
3.33000E+00 8.95873E-05
3.55200E+00 9.62846E-05
3.77400E+00 1.02982E-04
3.99600E+00 1.09679E-04
4.21800E+00 1.16377E-04
4.44000E+00 1.23074E-04
4.66200E+00 1.29772E-04
4.88400E+00 1.36469E-04
5.10600E+00 1.43167E-04
5.32800E+00 1.49864E-04
5.55000E+00 1.56562E-04
5.77200E+00 1.63259E-04
5.99400E+00 1.69957E-04
6.21600E+00 1.76654E-04
6.43800E+00 1.83352E-04
6.66000E+00 1.90049E-04
6.88200E+00 1.96747E-04
7.10400E+00 2.03444E-04
7.32600E+00 2.10142E-04
7.54800E+00 2.16839E-04
7.77000E+00 2.23537E-04
7.99200E+00 2.30234E-04
8.21400E+00 2.36932E-04
8.43600E+00 2.43629E-04
8.65800E+00 2.50327E-04
8.88000E+00 2.57024E-04
9.10200E+00 2.63722E-04
9.32400E+00 2.70419E-04
9.54600E+00 2.77117E-04
9.76800E+00 2.83814E-04
9.99000E+00 2.90512E-04
1.02120E+01 2.97209E-04
1.04340E+01 3.03907E-04
1.06560E+01 3.10604E-04
1.08780E+01 3.17302E-04
1.11000E+01 3.23999E-04
1.13220E+01 3.30697E-04
1.15440E+01 3.37394E-04
1.17660E+01 3.44092E-04
1.19880E+01 3.50789E-04
1.22100E+01 3.57487E-04
1.24320E+01 3.64184E-04
1.26540E+01 3.70882E-04
1.28760E+01 3.77579E-04
1.30980E+01 3.84277E-04
1.33200E+01 3.90974E-04
1.35420E+01 3.97672E-04
1.37640E+01 4.04369E-04
1.39860E+01 4.11067E-04
1.42080E+01 4.17764E-04
1.44300E+01 4.24462E-04
1.46520E+01 4.31159E-04
1.48740E+01 4.37857E-04
1.50960E+01 4.44554E-04
1.53180E+01 4.51252E-04
1.55400E+01 4.57949E-04
1.57620E+01 4.64647E-04
1.59840E+01 4.71344E-04
1.62060E+01 4.78042E-04
................ ..............

[latslosh]

Not sure if this works with 12, but it worked for me with 11: Set an expert parameter

monitor digits = <desired number>

where desired number can be anything up to 16. This expert parameter is not available in the menu so you need to do it using the 'edit in command editor' (and may need to introduce a dummy expert parameter to be able to that...)

Hope that helps, latslosh.

[rogbrito]

Hi Sir latslosh ,

could you please, explain better for us? I´m looking for an explanation about it but I didn´t find it yet!.

Thanks.

Rogerio.

[latslosh]

From your ccl I'm guessing that you just want to export the monitor point data from the solver manager.

Normally you only get limited precision with the data so you have to do the following (and this isn't in the user manual...):
-introduce an expert parameter (usually I set multigrid to true) The only point of this is that you can now see the 'expert parameter' icon on the left
-right-click on the expert parameters and select 'edit in command editor'
-now add the 'monitor digits = 16' option to the list and specify your desired precision (16 is the highest)
-save, close and proceed as normal.
Your numerical results should now have sufficiently high precision...

hope that helps, latslosh

[rogbrito]

I will try to follow your hint (little wooden mallet)!

Thanks again.

Rogerio.

Originally Posted by latslosh

From your ccl I'm guessing that you just want to export the monitor point data from the solver manager.

Normally you only get limited precision with the data so you have to do the following (and this isn't in the user manual...):
-introduce an expert parameter (usually I set multigrid to true) The only point of this is that you can now see the 'expert parameter' icon on the left
-right-click on the expert parameters and select 'edit in command editor'
-now add the 'monitor digits = 16' option to the list and specify your desired precision (16 is the highest)
-save, close and proceed as normal.
Your numerical results should now have sufficiently high precision...

hope that helps, latslosh

[rogbrito]

Hi, it worked out very well.

Thanks so very much.

Rogerio.