Laminar Model
Hi,
I want to know if when I set the turbulence model to laminar CFX will solve exactly the Navier Stokes Equations. CFX user guide says: "Laminar flow is governed by the unsteady NavierStokes equation. The laminar option does not apply a turbulence model to the simulation and is only appropriate if the flow is laminar" So, the fact thar it doesn't apply a turbulence model means that the equation that is solved is the NSE? It seems true, but could be false I think. What I want to simulate is a Mixing Layer. I will start with a tangent hyperbolic profile and analyse its development until it gets turbulent, so I have a laminar flow. I want to know what CFX does solve for this case. Thanks 
Sounds like you need to read a basic CFD textbook. The laminar model is the Navier Stokes Equations, when you apply a turbulence model you then are talking about the Reynolds (or Fauve) averaged Navier Stokes equations. I recommend you read a CFD textbook to understand what the previous sentence is saying.
If your flow is laminar or just getting transitional a laminar model is probably OK. Sometimes you need the turbulence transition model, depends on the case. CFX supports both approaches. 
Thank you ghorrocks.
I'm starting my CFD study now I have a lot to learn. I asked this because one told me that in CFX solver the laminar model was not implemented with the NSE but also with a RANS with such parameters that approximate the NSE. Theoretically I know that laminar means NSE, without turbulence, but me question was how do the solver see this. Regards 
Offtopic, but I thought I'd let you know you have a very cool name, Mr. dos Reis.

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Ok Ghorrocks.
Thank you very much for your answer. Thanks Josh. 
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