turbo machinery problem

turbotel · March 16, 2011, 00:03

if my rotating domain's rpm is more than 100k rpm means why recommended to solve with 2 or 3 low rpms (ex: 10k, 30k & 70k rpm) and then to solve 100k rpm?
what's is the physics or logic beyond this?

Josh · March 16, 2011, 19:45

The fluid flow will likely be simpler at lower RPM. If the solution diverges at 10k RPM, then it definitely won't converge at 100k RPM. This allows you to analyze individual components (e.g., mesh, timestepping scheme, boundary conditions) with a simpler problem rather than diving right into the complex problem without verifying your model works.

March 16, 2011, 00:03	turbo machinery problem	#1
turbotel New Member Join Date: Nov 2010 Posts: 26 Rep Power: 16	if my rotating domain's rpm is more than 100k rpm means why recommended to solve with 2 or 3 low rpms (ex: 10k, 30k & 70k rpm) and then to solve 100k rpm? what's is the physics or logic beyond this?

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March 16, 2011, 19:45		#2
Josh Senior Member Joshua Counsil Join Date: Jul 2009 Location: Halifax, Nova Scotia, Canada Posts: 366 Rep Power: 18	The fluid flow will likely be simpler at lower RPM. If the solution diverges at 10k RPM, then it definitely won't converge at 100k RPM. This allows you to analyze individual components (e.g., mesh, timestepping scheme, boundary conditions) with a simpler problem rather than diving right into the complex problem without verifying your model works.