UDF to define the vector transport equation

mvee · August 31, 2012, 05:47

Hi

Through the UDS, scalar transport equation can be defined. I would like to define the vector transport equation. How can i define it?

regards
Mvee

Amir · August 31, 2012, 08:14

Hi,

You would need 3 UDSs as each component!

Bests,

mvee · September 3, 2012, 00:03

Hi Amir

Can you describe how and which UDS to use?

Mvee

Amir · September 3, 2012, 03:38

Quote:

Originally Posted by mvee

Hi Amir

Can you describe how and which UDS to use?

Mvee

Suppose you wanna model momentum equation via UDS. You have to define 3 UDSs; u, v and w; and provide appropriate transport terms such as convection, diffusion, unsteady and source terms for each of them. A UDS has a general form of transport equation which you can modify for your purpose.

Bests,

mvee · September 3, 2012, 04:07

Hi Amir

Problem: Welding arc simulation
Description:
1) No. of zones: 3
2) Solid zone: electrode and workpiece (copper)
3) Fluid: argon (electrically conductive)

Current is imposed on the electrode which passes from the fluid and workpiece (which is at zero potential). Due to the current electro-magnetic field is generated which is governed by Maxwell’s equation (consists of current continuity and potential vector equation). These equations are having same form as that of our NS equations.

I have defined one UDS for voltage to solve current continuity equation. In the similar form do you mean to define UDS for vector A. Can you describe how shall I follow for the physics mentioned above? Also the output of this UDS will go as source term in momentum equation.

Thanks
Mvee

Amir · September 3, 2012, 05:29

Quote:

Originally Posted by mvee

I have defined one UDS for voltage to solve current continuity equation. In the similar form do you mean to define UDS for vector A. Can you describe how shall I follow for the physics mentioned above? Also the output of this UDS will go as source term in momentum equation.

Hi,

Ok, you'll also need a vector transport equation. You can consider a vector transport equation as 3 scalar transport equation (one for each component) and model each of them via a UDS. Here you have a vector A, so define 3 UDS as Ax, Ay and Az as its components. So consider your vector equation and decompose it into 3 scalar equation. Finally with simple UDFs you can add each component of your added equations into each momentum components without any trouble.

Bests,

mvee · September 3, 2012, 06:13

Hi Amir

Thank you very much for your help, still have some doubt.
My algorithm will work in following manner -

(1) Current continuit equation: $\Delta\Phi$ =0 /* $\Phi$ = applied voltage and $\Delta$ = Laplacian operator*/

(2) current density, j = - $\sigma$ $\nabla\Phi$

(3) Potential vector equation: $\Delta\vec{A}$ = $\mu\vec{j}$

First and third point can be applied through UDS. How to interface (required to solve point 2) between point 1 and 3? Is it required UDF?

Amir · September 3, 2012, 07:34

Quote:

Originally Posted by mvee

(1) Current continuit equation: $\Delta\Phi$ =0 /* $\Phi$ = applied voltage and $\Delta$ = Laplacian operator*/

(2) current density, j = - $\sigma$ $\nabla\Phi$

(3) Potential vector equation: $\Delta\vec{A}$ = $\mu\vec{j}$

First and third point can be applied through UDS. How to interface (required to solve point 2) between point 1 and 3? Is it required UDF?

Dear friend,

It depends. It doesn't need to evaluate j explicitly if you just want to obtain A! you can substitute j from equation 2 into 3 directly and remove the j variable. But if you want to obtain j as well; yes, you'll need a UDF to store the phi gradient into a UDM. It should be noted that you would also need UDFs for defining source terms of equation 3.

Bests,

mvee · September 10, 2012, 01:27

Hi Amir

Thank you very much for your kind co-operation. I have solved these equations.

Thank you
Mvee

mm.abdollahzadeh · October 30, 2022, 15:08

Quote:

Originally Posted by Amir

Dear friend,

It depends. It doesn't need to evaluate j explicitly if you just want to obtain A! you can substitute j from equation 2 into 3 directly and remove the j variable. But if you want to obtain j as well; yes, you'll need a UDF to store the phi gradient into a UDM. It should be noted that you would also need UDFs for defining source terms of equation 3.

Bests,

Hi amir, If you had any success with the plasma torch model can you share a case here?
I have developed a code for that but I am facing problem with converging temperature.

August 31, 2012, 05:47	UDF to define the vector transport equation	#1
mvee Senior Member Vaze Join Date: Jun 2009 Posts: 172 Rep Power: 16	Hi Through the UDS, scalar transport equation can be defined. I would like to define the vector transport equation. How can i define it? regards Mvee

August 31, 2012, 08:14		#2
Amir Senior Member Amir Join Date: May 2009 Location: Montreal, QC Posts: 735 Blog Entries: 1 Rep Power: 22	Hi, You would need 3 UDSs as each component! Bests, __________________ Amir

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September 3, 2012, 00:03		#3
mvee Senior Member Vaze Join Date: Jun 2009 Posts: 172 Rep Power: 16	Hi Amir Can you describe how and which UDS to use? Mvee

September 3, 2012, 04:07		#5
mvee Senior Member Vaze Join Date: Jun 2009 Posts: 172 Rep Power: 16	Hi Amir Problem: Welding arc simulation Description: 1) No. of zones: 3 2) Solid zone: electrode and workpiece (copper) 3) Fluid: argon (electrically conductive) Current is imposed on the electrode which passes from the fluid and workpiece (which is at zero potential). Due to the current electro-magnetic field is generated which is governed by Maxwell’s equation (consists of current continuity and potential vector equation). These equations are having same form as that of our NS equations. I have defined one UDS for voltage to solve current continuity equation. In the similar form do you mean to define UDS for vector A. Can you describe how shall I follow for the physics mentioned above? Also the output of this UDS will go as source term in momentum equation. Thanks Mvee

September 3, 2012, 06:13		#7
mvee Senior Member Vaze Join Date: Jun 2009 Posts: 172 Rep Power: 16	Hi Amir Thank you very much for your help, still have some doubt. My algorithm will work in following manner - (1) Current continuit equation: $\Delta\Phi$ =0 /* $\Phi$ = applied voltage and $\Delta$ = Laplacian operator*/ (2) current density, j = - $\sigma$ $\nabla\Phi$ (3) Potential vector equation: $\Delta\vec{A}$ = $\mu\vec{j}$ First and third point can be applied through UDS. How to interface (required to solve point 2) between point 1 and 3? Is it required UDF?

September 10, 2012, 01:27		#9
mvee Senior Member Vaze Join Date: Jun 2009 Posts: 172 Rep Power: 16	Hi Amir Thank you very much for your kind co-operation. I have solved these equations. Thank you Mvee