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a.maroofi September 21, 2010 07:43

uds in udf
I defiened a UDSI in unsteady time. I define such variable in my udf,
(C_T(c,t)-C_UDSI(c,t,0)), I see error

MASOUD September 21, 2010 23:05

Are you sure that the temperature and uds gradient have the same unit? If not you can't define such a term. That could be the reason.

a.maroofi September 22, 2010 01:04

uds in udf
thanks for your answer. yes, (C_UDSI(c,t)) and C_T(c,t) both are temperature in Kelvin

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