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uds in udf

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Old   September 21, 2010, 07:43
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arash
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I defiened a UDSI in unsteady time. I define such variable in my udf,
(C_T(c,t)-C_UDSI(c,t,0)), I see error
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Old   September 21, 2010, 23:05
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Are you sure that the temperature and uds gradient have the same unit? If not you can't define such a term. That could be the reason.
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Old   September 22, 2010, 01:04
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thanks for your answer. yes, (C_UDSI(c,t)) and C_T(c,t) both are temperature in Kelvin
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