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#1 |
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Member
Join Date: Mar 2013
Posts: 48
Rep Power: 14 ![]() |
hi
I had simulated a wind turbine using fluent and I want to calculate the output power(mechanical power) of it in different wind speeds . I don't know how to evaluate the output power. would you plz help me?? |
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#2 |
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Senior Member
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Power = Torque*omega.
Assume the axis of the rotor is in the z-direction, and you set the origin at the axis of your rotor, then torque is the z-moment. The omega is angular velocity you specified for the rotor. |
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#3 |
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Member
Join Date: Mar 2013
Posts: 48
Rep Power: 14 ![]() |
tnx a lot dear
it was really useful for me. i have another problem which my moment amounts are negative!!!! my flow comes from y- to y+ i had set my velocity inlet -11 and my rotation direction is +y would you plz help me??? |
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#4 | |
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Member
Join Date: Mar 2013
Posts: 48
Rep Power: 14 ![]() |
Quote:
i have got smaller amount for my simulation using your formula mentioned above. all of them are 100 order smaller: 46kw in stead of 4600kw would you plz help me to find the reason. |
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#5 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
i,m using the way that you mentioned in this forum but my results are about 10 times bigger than the exact amounts. i really need help .would you plz guide me???
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#7 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
my angular velocity is in rpm and i set it in units panel too. where can i change the cp in fluent???? or how can i totally reduce cp ??????
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#9 | |
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Member
Join Date: Mar 2013
Posts: 48
Rep Power: 14 ![]() |
Quote:
torque in fluent: 51084019 nm ang velocity:12 rpm |
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#10 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
my rated power : 5 MW torque in fluent: 51084019 nm ang velocity:12 rpm |
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#12 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
rotor diameter:63m rated wind velocity:11m/s rated ang velocity and my rotational velocity :12rpm |
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#13 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
rotor diameter:63m rated wind velocity:11m/s rated and velocity and my rotational velocity :12rpm |
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#15 |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
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#16 |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
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#18 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
in addition mass flow rate difference between inlet and outlet is 250 kg/s when the total inlet mass flow is 693639.75 kg/s axial velocity contour in y=0 plan |
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#20 | |
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New Member
Join Date: May 2013
Posts: 22
Rep Power: 14 ![]() |
Quote:
i had done what you told. please take a look at this photos and check if my solution is converged or not. in this situation the torque is 44944300
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