UDF for Heat Flux

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 April 11, 2014, 05:16 UDF for Heat Flux #1 New Member   Kishan Kumar Jaiswal Join Date: Nov 2013 Posts: 4 Rep Power: 5 Dear all, I am trying to write udf for heat flux having the formula Q = 0.304/y*y*y but I am unable to do it. It always shows some error. Can anyone write udf for heat flux. y is the length. and Q is the heat flux acting on X-Y plane in Z direction. Geometry is a cube with dimension 10*5*0.005 all are in meters. Thanks. Last edited by kishan kumar jaiswal; April 11, 2014 at 07:18.

 April 11, 2014, 10:08 #2 Senior Member     Flavio Join Date: Sep 2011 Location: Brescia, Italy Posts: 181 Rep Power: 8 Hello kishan, is this a boundary condition? In this case I suggest reading Fluent UDF Manual about DEFINE_PROFILE. Regards __________________ Bionico

 April 12, 2014, 01:35 #3 New Member   Kishan Kumar Jaiswal Join Date: Nov 2013 Posts: 4 Rep Power: 5 Dear Bionico, Thanks for your reply. Yes Its a boundary condition. I am doing the same as u suggested in your reply. but I don't know where I am wrong.

 April 14, 2014, 02:01 #4 Senior Member     Flavio Join Date: Sep 2011 Location: Brescia, Italy Posts: 181 Rep Power: 8 Hello, can you post your UDF, please? Regards __________________ Bionico

 April 21, 2014, 18:01 #5 New Member   Kishan Kumar Jaiswal Join Date: Nov 2013 Posts: 4 Rep Power: 5 Dear friend, There are some changes introduced in the formula, right now it is Q(Y) = (0.304)/(deltaY + deltaY/2)^-3 Where deltaY = 50cm and Y = 10m Y is the length on Y-axis and X whixh is equal to 5m is length on X-axis. Q is heat flux apply on the X-Y plane towards the Z direction. Geometry is a cube with dimension 10*5*0.005 all are in meters. If possible please help Regards, Kishan

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