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December 2, 2014, 04:20
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boundary condition rotating domain
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#1 |
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Senior Member
Join Date: Oct 2014
Posts: 124
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Hi everybody.
I am simulating a rotating domain of a water wheel. In the lateral surfaces of the rotating domain, which are in contact with the external open ambient, I have used pressure outlet=gauge pressure =0. The operative pressure is 101300 Pa. It is correct? I see that inside the rotating domain, the air flows at 40 m/s, which is totally wrong and I can't understand why. If I use symmetry instead pressure outlet this bad result doesn't appear, but, since there is not contact with the open ambient, the inside pressure becomes wrong. Anyone can help me? Thank you |
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| Tags |
| pressure outlet, rotating domain, symmetry, turbine |
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