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#1 |
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Member
Mattia
Join Date: Mar 2018
Posts: 45
Rep Power: 9 ![]() |
Hi, can any of you give me an advice regarding how to simulate open space with Fluent?
In my model I need to extract the surface temperatures of an heat exchanger in open space, the device is positioned at a certain distance from the floor and a wall. In order to reduce the number of elements I used simmetry on one side. I placed the heat exchanger into a limited volume of air. If I assign the wall boundary condition to the walls that surround the air volume it would be like simulate the heat exchanger into a box, so is there a way to assign an open space-like B.C. to these walls? Thanks very much |
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#2 |
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Senior Member
Join Date: Dec 2016
Posts: 152
Rep Power: 12 ![]() |
Can you post a pic of your fluid domain with arrows pointing to your boundaries, and what conditions you assign them?
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#3 |
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Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,845
Rep Power: 68 ![]() ![]() ![]() |
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#4 |
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Member
Mattia
Join Date: Mar 2018
Posts: 45
Rep Power: 9 ![]() |
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#5 |
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Member
Mattia
Join Date: Mar 2018
Posts: 45
Rep Power: 9 ![]() |
I have another question: in order to use pressure inlet or pressure outlet I should set the Gauge Pressure to zero right? The operating pressure is still at default value
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#6 | |
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Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,845
Rep Power: 68 ![]() ![]() ![]() |
Quote:
Right... If you keep the default operating pressure (which is ~1 atm) and set a zero gauge pressure, then your boundary condition is ~1atm of absolute static pressure. |
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#7 | |
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Member
Mattia
Join Date: Mar 2018
Posts: 45
Rep Power: 9 ![]() |
Quote:
I have a radiator that hang on a wall, the radiator has n eletric resistance inside and i want to know what will be the surface temperature at steady state. That is why I needed the open space like BC. Unfortunately using the pressure inlet or pressure outlet I can't reach a satisfying solution, probably i'm missing something again. I'm using pressure based solver, the resistance is a parallelepiped that is not included into the domain, I just gave the W/m2 distribution at the surfaces that represent the resistence. The resistence is in contact both with the raditator and the air. |
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#8 |
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Member
Mattia
Join Date: Mar 2018
Posts: 45
Rep Power: 9 ![]() |
Another question: even though I impose a certain energy flux on the surfaces of the resistance the fluid fluxes are all wrong. Instead of having hot air going versus the top of the volume , air just enter from the top side of the pressure inlet and exit from the bottom. I tried to cheat by puttting a pressure outlet on the top of the volume but the direction of the flux doesn't change.
Any suggestion? I'm using k-epsilon turbulence model, s2s, pressure based solver Thank you |
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