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Dividing Objects Symmetry

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Old   March 30, 2020, 00:07
Default Dividing Objects Symmetry
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Babal Cobelt
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Hey,

I want to simulate the flow of air with the heat transfer process on the square pipe with a very small size (side width of 3 mm). Because of its small size, I can only make it with a small amount of mesh so the results are not accurate.

To get more accurate results and shorten the simulation time, I divided the square pipe into 4 parts of symmetry and performed a simulation on one of these parts.

I have tried it but the results are not like a part of a 1/4 square pipe, but like a part of a complete pipe but with the size of 1/4 its original size.

How do you make the 1/4 part of the square pipe really represent the state of the real 1/4 part of the whole square pipe?
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Old   March 30, 2020, 01:07
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You will need to put symmetries on the two sides that would be on the inside of the pipe. For example, if you wanted to model the top-right 1/4 of the pipe, the top and right bc must be a wall, however the bottom and left bc must be a symmetry.
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Old   March 30, 2020, 02:37
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Thank you for your response

In this case I have tried it with the bottom-left 1/4 of the pipe, the bottom and left b.c. are the walls, and the top and right b.c. are symmetry with adiabatic condition.
But the result remains like a whole square pipe with 1/4 size of the original, while the process in it does not describe its condition which is 1/4 part.
For example: the air flow in 1/4 of the pipe is centered at the blue dot like the following picture, which should be in the top right corner like the original.

Last edited by babalcobelt; March 30, 2020 at 03:53.
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Old   March 30, 2020, 03:51
Default Symmetry
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If you use symmetry, then you won't get an option to apply adiabatic condition or any condition for that matter. Symmetry automatically implies adiabatic condition. So, in case after applying symmetry you still get an option for thermal condition where you can apply adiabatic, then that is not symmetry condition. Other option is to use Wall with Specified Shear of 0 and adiabatic. As long as there is no field other than flow, turbulence, and thermal, this would behave like symmetry.
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Old   March 30, 2020, 04:23
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Got it

Thank you
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heat-transfer, quarter-section, square-channel, square-pipe


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