How to simulate ...Interface..???

December 30, 2001, 02:11

Hi all,

For open channel flow, the top surface is an air-water interface. What Boundary condition is to be set to the top surface? I mean what parameters should be given as input for proper simulation of the interface? And how to do it???

I had set "Interface" B.C. in GAMBIT. While setting the BCs in Fluent5, in "Boundary conditions" panel there is nothing to set for "Interface". How does FLUENT treat the Interface?

I tried to search Fluent as well as Gambit Manuals but could not get any information on it.

Please help..

Sharad Dugad

January 2, 2002, 02:04

If you want to calculate water flow with the air interface, proper boundary condition is 'symmetry' because shear force is negligible. If you want to calculate two-phase flow(air-water flow), you should use the VOF model.

Sincerely, Jinwook

January 18, 2002, 05:14

Doesn't symmetry assume that there is water on the other side of the interface ?

December 30, 2001, 02:11	How to simulate ...Interface..???	#1
Sharad Dugad Guest Posts: n/a	Hi all, For open channel flow, the top surface is an air-water interface. What Boundary condition is to be set to the top surface? I mean what parameters should be given as input for proper simulation of the interface? And how to do it??? I had set "Interface" B.C. in GAMBIT. While setting the BCs in Fluent5, in "Boundary conditions" panel there is nothing to set for "Interface". How does FLUENT treat the Interface? I tried to search Fluent as well as Gambit Manuals but could not get any information on it. Please help.. Sharad Dugad

January 2, 2002, 02:04	Re: How to simulate ...Interface..???	#2
Jin-Wook LEE Guest Posts: n/a	If you want to calculate water flow with the air interface, proper boundary condition is 'symmetry' because shear force is negligible. If you want to calculate two-phase flow(air-water flow), you should use the VOF model. Sincerely, Jinwook

January 18, 2002, 05:14	Re: How to simulate ...Interface..???	#3
Sugen Chetty Guest Posts: n/a	Doesn't symmetry assume that there is water on the other side of the interface ?

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