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January 31, 2005, 10:15 
buoyancy driven flow

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January 31, 2005, 14:12 
Re: buoyancy driven flow

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Instead of using incompressible ideal gas, try ideal gas. I think that should account for pressure, although I've never actually tried such a problem.


February 1, 2005, 04:46 
Re: buoyancy driven flow

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thanks for respond, Ideal gas will be even worse... If I used ideal gas, fluent will calculate the density according to current pressure (density=(operating pressure+local pressure)/(R/M*T). This will take into account the local pressure which is lower due to the assumption of removed hydrostatic pressure and thus the density will be also much lower. Then the density will have impact on sollution of the Boussinesq term in momentum equation. I am just not sure wether ideal gas or incmopressible ideal gas will better fit to the problem. It is sad that I cannot find much about it in the UG. regards adam


February 10, 2005, 13:26 
Re: buoyancy driven flow

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hi,
I performed a similar simulation. If you set the operating pressure to zero you obtain that local pressure=absolute pressure, the density should be calculated in a rigth way. But after that I had a lot of troubles with the turbulence values, TKE especially. regards, giorgio 

February 11, 2005, 04:44 
Re: buoyancy driven flow

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Hi Giorgio, Yes, you're right but did you have large difference in altitute? If you do, you need to redefine the pressure due to the hydrostatic head. The redefined static pressure is p's=psrho0*g*h. It doesn't matter if it is absolute or gauge  it is lower and the calculated density is also lower. Probably it is necessary to define my own formula for density calculation by UDF. Regards


February 11, 2005, 05:55 
Re: buoyancy driven flow

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Hi Adam,
in my simulations the height of the domain was 1 km. The formula you've writted is valid only if rho is constant. In the hydrostatic approximation you have to integrate the hydrostatic law from the ground to the top of your domain. Inside the integral form you have rho=rho(pressure(z), temperature(z)) so calculate this integral and you get a vertical pressure profile p=p(z) with z the altitude. Build a pressure profile file to import in fluent. I applied this profile at the outlet (pressure outlet) while at the inlet I had set the inlet as velocity inlet. It should work Giorgio 

February 14, 2005, 05:11 
Re: buoyancy driven flow

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Hello Giorgio, I have Pressure Inlet and pressure Outlet BC's. The pressure inlet is vertical ca 600m high and pressure outlet is horisontal at the top. Fluent calculates velocity at the pressure inlet from Bernoulli's equation (for incompressible). If I would have difference in inputs between p. inlet and p. outlet, a flow would appear, even there nothing flows in reality. If I calculate the integral you said I will get p = p0*exp(g*x/(RT)). Therefore pressure to be input at the boundary must be constant: ps = pop  p0*exp(g*x/RT). To the obtained pressure field I must add the hydrostatic head p0*exp(g*x/(RT)). The problem is with density. The density also chanegs with height as rho = rho0*exp(g*x/RT). If I used incompressible ideal gas or ideal gas for density calculations the density would be calculatedc as rho = pop/(RT) and rho = (pop + p)/(RT) respectively. In both cases it seems to be wrong since in first it does not depend on pressure in the system and in the second p is very low everywhere in the system and density will also be low. I tried to apply rho = rho0*exp(g*x/RT) for density calculation throuh UDF but it takes ages to do one iteration and difficulties with divergence appeared... So far I cannot see any solution for that... regards Adam


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