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Methane combustion
Has anyone tried the Jones and Lindstedt four equation mechanism for methane combustion in Fluent?
I have implemented the four steps in the "propdb.scm" file. It works fine for the EDM, but when EDC is activated Fluent gives the error message: ********** ISAT_ABORT ************** routine = phi2y location = 1 message = non-positive species sum ****** END ISAT_ABORT ************** Error: isat terminated. Error Object: #f Does anyone know how to implement this mechanism in Fluent so the EDC works? Steve |
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Hi San Siro
At that time I contacted Fluent support and they said I had to use a Chemkin file. They even provided me the file. It's named 4_reactions.che and I attached it below. As far as I remembered the Chemkin file ran smoothly with the EDC model in Fluent 5.3 and 6. I hope it will work for you as well.
Kind regards Steve ---------------- ELEMENTS H O C N END SPECIES CH4 O2 CO2 CO H2O H2 N2 END THERMO END REACTIONS KJOULES/MOLE !Units are cm, mol, s, kJ/mol and K. 2CH4+O2=>2CO+4H2 7.824435194e13 0.0 0.12552 FORD/CH4 0.5/O2 1.25/ CH4+H2O=>CO+3H2 3.1E11 0.0 0.12552 CO+H2O=>CO2+H2 2.75E12 0.0 0.08368 2H2+O2<=>2H2O 4.44566E21 -1.0 0.16736 FORD/H2 0.5/O2 2.25/ RORD/H2O -1.0/ END |
HI
When I used the laminal finite-rate model to simulate a reaction involves both volumetric reactions and wall surface reactions,I selected the Two-Step Solution Procedure.I begin by solving the flow, energy, and species equations with reactions disabled.When the basic flow pattern has been established,I enable the reactions and continue the calculation.
Then fluent gives the error message: Error: Non-physical Specific Heat = 0.000000e+000. Error Object: () I ignore the message and continue to calculate,fluent gives the following error message: Error: isat terminated. Error Object: (). This problem has troubled me for a long time.Is there any suggestions how can I solve this problem and continue my calculation. Thank San Siro |
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--- Edit: My guess so far is that adding a minus or plus sign mean a correction on the order. Anybody can confirm? |
The H2 + 0.5 O2 --> H2O reaction is a global one and it includes several elementary steps with many reactive intermediates like H, O, OH. Such global reactions have complicated rate laws. The reaction orders are usually not integers and they can be negative.
You can probably find some more details, if you are interested, in Warnatz, Maas and Dibble's textbook "Combustion." |
And of course, a negative reaction order means the rate decreases when the concentration of that component increases
r = k(T) [H2]^0.5 [O2]^2.25 [H2O]^(-1) = k(T) [H2]^0.5 [O2]^2.25 / [H2O] |
Thanks for your reply.
It is still not clear to me. I thought the chemkin format means: r = kf(T) [H2]^0.5 [O2]^2.25 - kb(T) [H2O]^(-1) kf: forward constant kb: reverse constant Of course, put this way, it does not make sense (as the product decrease, the reverse kinetic increase). Looking at the file, it seems that the reaction is considered reversible. The way you put it, I don't see how it can be reversible. |
Yes, you are correct.
2H2+O2<=>2H2O is often simplified to be non-reversible and represented by r = k(T) [H2]^0.5 [O2]^2.25 [H2O]^(-1). But according to the Chemkin output, as you noticed, it isn't the case. The reaction seems to be reversible with a reaction order of -1. |
Different version of chemkin
Hi
I just wonder if the chemkin file that is available in Fluent can be older version of chemkin. I use CHEMKIN-II Version 3.1 and do not think it allows me to enter the reaction order. Has anyone ever tried to use the Jones and Lindstedt mechanism with my version of chemkin? Thank you in advance |
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Tried this in my fluent, but its showing floating point error. Can Somebody please guide me through this? |
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