# PIPES TURBULENCE DROP PRESSURE

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 August 6, 2007, 08:47 PIPES TURBULENCE DROP PRESSURE #1 beginner Guest   Posts: n/a Hello everybody, I made a modelisation with the following parameters and i try to get the the skin friction factor in the lenght of the pipe this for different roughness. 3D inlet 0.015 m/s D= 1m L=20m water -> Re=15 000 symmetry pipe divided into two part. Trying different times with : Solver K-epsilon: Ks=5e-5 -> Cf=1.5e-3 f=4*Cf=6e-3 Ks=2e-2 idem same value for Cf I mean that the cavities of the roughness has an average diameter equal to 5e-5 m or 2e-2m. whereas i expect according MOODY diagramme f=1.8e-3 I try with omega model i get a different Cf but still similar for the model. I make maybe a misunderstanding with Ks; If somebody would have a suggestion i would be very helpful. BB

 August 7, 2007, 12:06 Re: PIPES TURBULENCE DROP PRESSURE #2 chouaib Guest   Posts: n/a You can make an equivalence with the Nukeradse`s roughness and the Fluent parameters of roughness (roughness height and roughness constant). Chouaib

 August 15, 2007, 15:48 Re: PIPES TURBULENCE DROP PRESSURE #3 beginner Guest   Posts: n/a THANK YOU SORRY FOR BEING SO LATE

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