Wall jet(please help me urgent)

maryam · November 12, 2009, 10:52

Hello every body,
I want to simulate wall jet with Re=1000 and Velocity= 1m/s ,
now I generated mesh and imported to fluent,

I set all of data in fluent , I use a 2d box with 220mm hieght, 1000mm lenght and 10 mm slot width,

now I want to define boundary condition for it( inlet velocity for slot width, out let pressure for end of surface, no slip for bottom wall) and I don't know what can I do with top wall or free surface, I used pressure inlet and another time, wall specified shear but my simulation was wrong, please help me.

or if you know about jet tutorial please guide me.

thanks
maryam ( m_amiraftabi@yahoo.com)

bob12 · November 12, 2009, 13:59

hi
i think that you try simmetry condiction on the top, i know in real there isn't but it resolve the problem.
i hope had a good

maryam · November 12, 2009, 15:34

hi Dear bob12
thank you for your help, but if I use symmetric boundary condition, may be I have another slot on the top of the wall, is this trick possible?
or I should use a taller wall for example 2 meters instead of 0.22 meters!!
I don't know please help.
thank you

Chris D · November 12, 2009, 17:49

Quote:

Originally Posted by maryam

Hello every body,
I want to simulate wall jet with Re=1000 and Velocity= 1m/s ,
now I generated mesh and imported to fluent,

I set all of data in fluent , I use a 2d box with 220mm hieght, 1000mm lenght and 10 mm slot width,

now I want to define boundary condition for it( inlet velocity for slot width, out let pressure for end of surface, no slip for bottom wall) and I don't know what can I do with top wall or free surface, I used pressure inlet and another time, wall specified shear but my simulation was wrong, please help me.

or if you know about jet tutorial please guide me.

thanks
maryam ( m_amiraftabi@yahoo.com)

Have you tried pressure outlet for the top boundary?

bob12 · November 13, 2009, 01:41

you try the simulation with the condiction that you have but on the top simmetry, if you don't give the command of periodic fluent doesn't another slot becouse for create another slot there is a proper command.
i'm not very pratice with the programm but i hope that is helpful you.

November 12, 2009, 15:34	tnx	#3
maryam New Member Maryam Amiraftabi Join Date: Nov 2009 Posts: 9 Rep Power: 16	hi Dear bob12 thank you for your help, but if I use symmetric boundary condition, may be I have another slot on the top of the wall, is this trick possible? or I should use a taller wall for example 2 meters instead of 0.22 meters!! I don't know please help. thank you

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November 12, 2009, 13:59		#2
bob12 Member Join Date: Oct 2009 Location: Italy Posts: 88 Rep Power: 16	hi i think that you try simmetry condiction on the top, i know in real there isn't but it resolve the problem. i hope had a good

November 13, 2009, 01:41		#5
bob12 Member Join Date: Oct 2009 Location: Italy Posts: 88 Rep Power: 16	you try the simulation with the condiction that you have but on the top simmetry, if you don't give the command of periodic fluent doesn't another slot becouse for create another slot there is a proper command. i'm not very pratice with the programm but i hope that is helpful you.