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August 27, 2018, 21:19 |
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#21 |
Senior Member
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What you have replied is a rather old thread. By any chance did you choose incompressible fluid rather than ideal gas in your setup?
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August 27, 2018, 23:14 |
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#22 |
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vektor
Join Date: Aug 2018
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that's a possibility i am gonna repeat the steps again, and make sure i don't miss anything. honestly i didn't choose either of them.
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August 27, 2018, 23:24 |
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#23 |
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vektor
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August 28, 2018, 00:57 |
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#24 | |
New Member
vektor
Join Date: Aug 2018
Posts: 23
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Quote:
here is the video of what i did in fluent https://youtu.be/DZOyHQQs4rk |
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August 28, 2018, 01:36 |
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#25 |
Senior Member
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You have to set the material property for the computation. By default the fluid is assumed to be incompressible but you have to change it to ideal gas law in this case. Also, please make sure that your domain range is exactly as the comment of the UDF stated.
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August 28, 2018, 01:45 |
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#26 | |
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vektor
Join Date: Aug 2018
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Quote:
IT WORKED, i changed the density from constant to ideal gas and the changed the solver from pressure driven to density driven, and i got a nice contour, it looks better, i still need to tweak some variable a little bit, i believe the domain is right it's like this: [X]: from 0 to 10 meters [Y]: from -0.1 to 0.1 meters [Z]: from -1 to 1 meters i tried with low resolution mesh of 20x20x1 |
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August 29, 2018, 00:19 |
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#27 | |
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vektor
Join Date: Aug 2018
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Quote:
so i just discovered that somehow after initializing using the udf, i get wrong densities right away |
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August 29, 2018, 01:23 |
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#28 |
Senior Member
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What fluid do you use in your computation? Did you type in the code rather than copy& paste? The pressure ratio is 10 (1e5 versus 1e5) and the temperature ratio is 1.25, which according to the ideal gas law will lead to a density ratio of 8, no matter whatever the fluid is. But in your figure, the density ratio is no more than 1.5, so in your code either the temperature ratio is not 1.25, or the pressure ratio is not 10.
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September 6, 2018, 00:21 |
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#29 | |
New Member
vektor
Join Date: Aug 2018
Posts: 23
Rep Power: 8 |
Quote:
hi, i am sorry. i just didn't set the operation pressure to zero, i finally got extremely accurate results using ausm scheme. thank you, but i am still not sure what the operating pressure means, is it like the static or atmospheric pressure? thanks |
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shock tube, simulation |
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