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February 22, 2011, 07:48 |
initial condition in unsteady
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#1 |
Senior Member
hamid
Join Date: Nov 2010
Posts: 185
Rep Power: 15 |
Hi!
Speaking for unsteady problem If u don’t know the initial condition, are the following approaches correct? 1. You may just guess the i.c. solving first in steady-state until well converge and then using it as i.c. for unsteady OR 2. Using any arbitrary i.c. while it is solving unsteady and after some amount of time (or cycles if you have cyclic b.c.) we have reliable result –of course all in case of well converge- |
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February 22, 2011, 11:28 |
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#3 |
Senior Member
hamid
Join Date: Nov 2010
Posts: 185
Rep Power: 15 |
Yes , I know my question is stupid… if y=f(x,t) then it is function of t as well as x, but something is vague for me when using a numerical approach CFD (like fluent), it is obvious that the initial condition they use in fluent is not a real i.c. because just for example the i.c. is basically the same for whole domain which is not correct in real physic or happens very rare, but as far as I know this Not correct i.c. will be vanished during the steps/time/solution, May be I am completely wrong:-D
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