# udf T（ni）=T（ni-1）

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 June 22, 2011, 12:20 udf T（ni）=T（ni-1） #1 New Member   anonymous Join Date: Nov 2010 Posts: 6 Rep Power: 8 Hi, I want to define boundary conditions of T and Yi as T（ni）=T（ni-1）and Yi(ni)=Yi(ni-1), but I don't know how to achieve it by UDF, thx for your help.

 June 22, 2011, 12:24 #2 Member   Nuno Gomes Join Date: May 2009 Location: Portugal Posts: 39 Rep Power: 10 n is node number?

June 22, 2011, 12:30
#3
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anonymous
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Quote:
 Originally Posted by Dinocrack n is node number?
yes, ni represent the last node in x axis，thanks

June 22, 2011, 21:54
#4
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anonymous
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Quote:
 Originally Posted by yc9316 yes, ni represent the last node in x axis，thanks
I means make varible(Ni,J,K)=varible(Ni-1,J,K), can it be defined as UDF? regards.

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