|
[Sponsors] |
![]() |
![]() |
#1 |
New Member
Hamid
Join Date: Mar 2012
Posts: 20
Rep Power: 15 ![]() |
Hello CFD guys,
I'm trying to generate turbulent channel flow using wall resolved LES simulation on a collocated block structured, multi-grid accelerated finite volume code. I defined periodic boundaries on the horizontal plane, symmetry on top and no slip wall (no model) for the bottom and started with a log profile with some random noise (10-50% magnitude). The problem is the fluctuations are damped rather quickly. u_tau=1, domain: 0.5pi x 1 x pi with 48*48*48 grids (uniform in horizontal direction and stretched in the vertical with the first grid in yplus=0.25). This could partly make sense as the initial fluctuations are not correlated etc. but there is also a suspicion that since the code is is not pseudo-spectral (unlike many available codes) and is collocated, it's highly dissipative and also not kinetic energy conserving. What is your opinion? Do you have any idea how I should generate the correct turbulence filed? My code has also the problem that the finer the mesh is, the more dissipative it becomes, isn't it strange? |
|
![]() |
![]() |
![]() |
![]() |
#2 | |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,964
Rep Power: 73 ![]() ![]() ![]() |
Quote:
The first issue is that LES is a 3D simulation, you must solve the entire 3D channel, no simmetry at half-height ... you are forcing a false solution |
||
![]() |
![]() |
![]() |
![]() |
#3 |
Senior Member
cfdnewbie
Join Date: Mar 2010
Posts: 557
Rep Power: 21 ![]() |
||
![]() |
![]() |
![]() |
![]() |
#4 |
New Member
Hamid
Join Date: Mar 2012
Posts: 20
Rep Power: 15 ![]() |
||
![]() |
![]() |
![]() |
![]() |
#5 | |
New Member
Hamid
Join Date: Mar 2012
Posts: 20
Rep Power: 15 ![]() |
Quote:
That's a good point and I agree that LES is in fact 3D, but does it mean you are never allowed to use symmetry BC in LES? Cause I've seen quite a few papers (mainly atmospheric boundary layer simulations) that have set the top BC as a symmetric surface (I guess they've presumed that the top of the domain can be treated like a laminar flow) |
||
![]() |
![]() |
![]() |
![]() |
#6 |
Super Moderator
Alex
Join Date: Jun 2012
Location: Germany
Posts: 3,430
Rep Power: 49 ![]() ![]() |
There are circumstances when a symmetry boundary condition can be applied in LES. The main prerequisite is that the flow is laminar next to the boundary.
For a turbulent channel flow, this condition is not satisfied. |
|
![]() |
![]() |
![]() |
![]() |
#7 |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,964
Rep Power: 73 ![]() ![]() ![]() |
in channel flow with LES the condition of simmetry is simply wrong and drives the flow to dissipate artificially the energy ... such a condition can be used in RANS simulation where the variable which is solved has a steady statistical meaning.
Furthermore, I suggest to run the full 3D case with and without SGS model, on the same grid, to assess the real effect of the model... |
|
![]() |
![]() |
![]() |
Tags |
channel flow, les, turbulence, wall resolved |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
Open Channel Flow | ElanMorin | FLUENT | 4 | February 25, 2015 16:26 |
turbulent developed lenght in oppen channel flow | zandi | Main CFD Forum | 0 | January 9, 2010 14:52 |
Initial conditionfor turbulent channel flow in LES | pankaj saha | Main CFD Forum | 0 | November 30, 2007 12:04 |
Turbulent channel flow | roberthino | OpenFOAM Running, Solving & CFD | 5 | August 15, 2007 08:35 |
Pressure drop across a turbulent channel flow | shiv | Main CFD Forum | 0 | September 21, 2005 00:52 |