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September 27, 2012, 05:33 |
Integral form of the Burger's equation
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#1 |
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Join Date: Jun 2010
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Hi, Can someone tell me what the integral form of the inviscid Burger's equation is? I know the differential form. Confused on how to write the integral form of the u(du/dx) term.
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September 27, 2012, 08:36 |
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#2 | |
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Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,764
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Quote:
du/dt + d (u^2/2)/dx =0 --> Int (du/dt) dx + [u^2|x+dx/2 - u^2|x-dx/2 ]/2 = 0 |
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