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September 3, 2013, 14:42 |
A silly question about turbulent flow
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#1 |
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I wonder why we sometimes can apply steady state in the modelling of turbulent flow
Many thanks |
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September 3, 2013, 15:11 |
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#2 |
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Because in such cases (Reynolds-averaged Navier Stokes) you are solving for the mean quantities from the Reynolds averaging. These quantities are considered to be steady, since any time dependency has been averaged out.
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September 15, 2013, 15:35 |
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#3 |
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September 15, 2013, 21:11 |
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#4 |
Senior Member
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