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November 15, 2006, 22:46 
kinetic energy

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November 16, 2006, 01:56 
Re: kinetic energy

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Hai! i think u want the KE of each fluid partical in the cavity. if it is the case, i think u have to use the general formula (0.5*rho*V^2), where V is the total velocity of each individual partical


November 17, 2006, 00:21 
Re: kinetic energy

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im using E(nxdelt)=SUM((u(i,j)^2+v(i,j)^2)^0.5) where n is the no. of time step. and delt is the relaxation time. im using steady state equation with pseduo transient. is this formula right


November 17, 2006, 04:52 
Re: kinetic energy

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but what is SUM indicates! are u trying to find out the average velocity of all the particles, the u have to use the rms value. that formula u can get from kinetic theory of gases. and i want to know exactly what u r doing!


November 17, 2006, 08:31 
Re: kinetic energy

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Your formula is for the average velocity on a uniform mesh, or for the L2 norm of the velocity. KE is proportional to the velocity squared, so you need to remove the square root. For KE, you need to multiply by 1/2 and by the density if your equations are not scaled so that the density is 1.
For a nonuniform mesh, you must multiply (or weight) the velocity squared at each node by a volume associated with the node. Some times mathematicians will refer to just the velocity squared as the kinetic energy, ignoring multiplicative constants, when establishing bounds on solutions. 

November 17, 2006, 09:31 
Re: kinetic energy

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Jonas,
Why do you need to weight velocity with the volume? Taking half of the square of the magnitude of the velocity vector and multiplying it by the density gives you kinetic energy per unit volume so it does not need any scaling even if the mesh is nonuniform. regards M.Lipinski 

November 18, 2006, 08:10 
Re: kinetic energy

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Re: M. Lipinski  "Taking half of the square of the magnitude of the velocity vector and multiplying it by the density gives you kinetic energy per unit volume" gives the KE at a point. jj is summing over the nodes of the mesh and hence calculating the total KE over the domain. By dimensional analysis, one must multiply (KE/vol) by a volume to get KE.


November 18, 2006, 09:55 
Re: kinetic energy

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OK Jonas, I see your point. Though I think that the KE/Vol (KE per unit volume) is something that is more interesting than KE. E.g. it will give you a constant value, in regions where RHO and velocity are constant, independent of the element size. On the other side, KE involves mass that is clearly element size dependent.
regards M.Lipinski 

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