|
[Sponsors] |
Application of SIMPLE method for solving steady state NS equation |
|
LinkBack | Thread Tools | Search this Thread | Display Modes |
January 25, 2014, 19:23 |
Application of SIMPLE method for solving steady state NS equation
|
#1 |
New Member
LA
Join Date: Jan 2014
Posts: 4
Rep Power: 12 |
Hi every one,
I am trying to model the developing incompressible steady state flow between flat plates (Poiseuille flow) in MATLAB. Staggered grid approach is used. The chosen boundary conditions are as follows: Extents of the domain: 0<x< L 0< y< h top and bottom @ y=0& y=h u=v=0 dp/dy=0 at left boundary @ x=0 v=0, u=const. (uniform across the boundary) p1=p2-(p3-p2)*0.5 x=0; at the right boundary@x=L dp/dx=0, du/dx=0, dv/dx=0 SIMPLE procedure was used for solving the equation and iterations. The problem is that the pressure correction equation is not giving a unique solution. I have checked the equations and it satisfies the boundary condition and discretisation procedure. I want to know how to correct the pressure correction equation. Pressure correction at the right boundary is zero. I have a taken a linear pressure profile as my initial guess for the problem. So, the pressure correction for the grid points in the top and bottom boundary is same as the pressure correction of the adjacent nodes in the Y direction. Kindly suggest possible corrections and prospective deviations in the method. |
|
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
unsteady state to steady state | neetu kumari | OpenFOAM | 4 | June 14, 2016 19:16 |
outflow boundary in a steady state 1D convection diffusion eq. | hans-186 | Main CFD Forum | 2 | October 14, 2012 18:39 |
under relaxation factor and the steady state | jing113cn | FLUENT | 0 | November 2, 2009 13:13 |
Steady State 2 phase problem | fivos | FLUENT | 0 | April 27, 2009 17:34 |
About the difference between steady and unsteady problems | Lisa | Main CFD Forum | 11 | July 5, 2000 15:37 |