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4th order discretization of 2nd order difference

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Old   February 11, 2007, 03:01
Default 4th order discretization of 2nd order difference
  #1
dusky.He
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Does anyone can tell me the form of 4th-order discretization of 2-order difference in cylindrical coordinate.

In Cartesian coordinate, it is (-F(i-2)+16F(i-1)-30F(i)+16F(i+1)-F(i+2))/(12*dx)
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Old   February 12, 2007, 00:36
Default Re: 4th order discretization of 2nd order differen
  #2
Harish
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If you have mathematica/maple/maxima you can find the coefficients using it.Also look for the paper on compact scheme by sanjeev lele ( JCP 1992),it should give you the required finite difference discretization.

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Old   February 14, 2007, 04:16
Default Re: 4th order discretization of 2nd order differen
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Chandra
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discretization is independent of co-ordinate system [d2u/dx2 or d2u/dr2 are same]. If, whatever u have wrote, is correct in Cartesian co-ordinate, it is correct in Cylindrical co-ordinate as well. So, enjoy!! you already have what r u looking for

What changes with change in co-ordinate system is terms itself, not the way it is discretized.

hope it helps.
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Old   February 14, 2007, 08:00
Default Re: 4th order discretization of 2nd order differen
  #4
qunwuhe
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You are right, but I want to discretize the Lapace of Phi in cylindrical coordinate. So the divergence of a gradient in cylindrical is different from the one in Cartetian coordinate.
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