Why cavitation degrades the performance of a pump?

yhy20081016 · March 31, 2014, 04:31

It is common sense that cavitation degrades the performance of a pump (causing the head of the pump to drop). But I seldom see any book clearly explains why this happen. Some books says that performance degrades is due to blockage of the blade passage by the bubbles.
As I know, the head of the pump can be determined by the euler equation
$\Delta p=\rho(U_{2}V_{\theta2 }-U_{1}V_{theta 1})$
I wonder anybody have some idea explaining the cavitation induced head drop based on this equation.

tas38 · April 1, 2014, 16:38

You may want to take a look at the following book and the references therein:

http://authors.library.caltech.edu/25019/3/pumbook.pdf

For example, in Chapter 7 one possible explanation for the degradation of hydraulic performance is that voids located not on the suction side of the blades but rather under the shroud of a centrifugal pump may impact the angle with which flow leaves the impeller and significantly alter performance.

yhy20081016 · April 4, 2014, 01:37

Quote:

Originally Posted by tas38

You may want to take a look at the following book and the references therein:

http://authors.library.caltech.edu/25019/3/pumbook.pdf

For example, in Chapter 7 one possible explanation for the degradation of hydraulic performance is that voids located not on the suction side of the blades but rather under the shroud of a centrifugal pump may impact the angle with which flow leaves the impeller and significantly alter performance.

Thank you very much.

March 31, 2014, 04:31	Why cavitation degrades the performance of a pump?	#1
yhy20081016 Member yehanyu Join Date: Mar 2012 Location: Beijing, China Posts: 48 Rep Power: 14	It is common sense that cavitation degrades the performance of a pump (causing the head of the pump to drop). But I seldom see any book clearly explains why this happen. Some books says that performance degrades is due to blockage of the blade passage by the bubbles. As I know, the head of the pump can be determined by the euler equation $\Delta p=\rho(U_{2}V_{\theta2 }-U_{1}V_{theta 1})$ I wonder anybody have some idea explaining the cavitation induced head drop based on this equation.

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April 1, 2014, 16:38		#2
tas38 Senior Member Troy Snyder Join Date: Jul 2009 Location: Akron, OH Posts: 219 Rep Power: 18	You may want to take a look at the following book and the references therein: http://authors.library.caltech.edu/25019/3/pumbook.pdf For example, in Chapter 7 one possible explanation for the degradation of hydraulic performance is that voids located not on the suction side of the blades but rather under the shroud of a centrifugal pump may impact the angle with which flow leaves the impeller and significantly alter performance.