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June 12, 2007, 21:36
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difference scheme
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Guest
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I read a paper where an delta(u) is defined as u_j+1 - u_j and upside down delta(u) as u_j - u_j-1. What about the case of a delta with a two superscript? (like laplace operator?)
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June 12, 2007, 22:34
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Re: difference scheme
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Guest
Posts: n/a
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It may be a second-order differential term seen as (u_i+1-2u_i+u_i-1)/del^2
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