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any equation for nozzle shape profile?

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Old   September 2, 2014, 21:13
Default any equation for nozzle shape profile?
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Kan
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Hi,

I am now trying to validate my conjugate heat transfer solver with a nozzle experiment, the description about that nozzle is shown as follows:

The test nozzle is axisymmetric, has
a throat diameter of 0.0458 m, a contraction-area ratio of 7.75:1, an
expansion-area ratio of 2.68:1, a convergent half-angle of 30 deg,
and a divergent half-angle of 15 deg


How can I draw the nozzle shape profile based on this given information? is there any equation for nozzle shape?

Cheers,
Kan
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Old   September 2, 2014, 23:52
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I am not sure if this is what you are looking for. However, I have done a problem that involved generating a nozzle shape. It simplified the geometry by representing the curves as sinusoidal.

Perhaps you can generate the outline of the nozzle boundary by dividing it into 6 curves (or I guess just 4 as the converging and diverging sections are to be reflected). One curve represents the inlet and a second curve represents the outlet. These are obviously described by vertical lines (for which you may find the height using area ratios and the throat diameter).

The third curve is for the converging portion. Assuming the horizontal axis (y = 0) divides the nozzle, the third curve is of the form
y_n = -c_1 \cos\left(\frac{\pi(x-c_3)}{c_2-c_3}\right)
where c_1 represents the vertical difference between the top of the inlet and the top of the throat, c_2 represents the horizontal location of the throat, and c_3 represents the horizontal location of the inlet. Reflect this across the x axis for the fourth curve.

The fifth curve describes the diverging section. The curve may be represented the same way:
y_n = b_1 \cos\left(\frac{\pi(x-c_2)}{b_2-c_2}\right)
where b_1 represents the vertical difference between the top of the outlet and the top of the throat and b_2 represents the horizontal location of the outlet. Reflect this across the x axis for the sixth curve.

Maybe you can shift the curves in order to satisfy your converging and diverging angle criteria. Good luck.

Last edited by j_02; September 3, 2014 at 09:44. Reason: typo
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