# What is the Boussinesq Term in Momentum Equation

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 August 11, 2008, 09:56 What is the Boussinesq Term in Momentum Equation #1 CFDtoy Guest   Posts: n/a In the momentum equation, what is the correct representation of the bousinessq body force term? d(dhoU)/dt+conv term = -gradP + rho*(1-beta*(T-Tref)) or simply d(dhoU)/dt+conv term = -gradP -beta*(T-Tref)) is the force term = rho*g where rho = rho(T) or simply the difference of actual density rho to reference density rho_0. Depending on the RHS, the source values are completely off-set. I am not sure if the source values are the differences in density of the actual body force (rho*g) where rho varies as rho = rho_0+rho_0*beta*(deltaT) In the second case, if its an isothermal situation, does it mean no gravity force is acting on the system? And, Should, the momentum equation give back simply the rho*g term is no density variation due to temperature changes are available? Thanks, CFDtoy

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